Ho vd ftn thi sinh:
56 bdo danh:

BQ GIAO DUC VA DAO TAO
DAI HQC HUE
t

KV THI TTIYEN SINH SAU DAI HQC NAM 2006
M6n thi: Co s& lf thuyiit HOahgc vir Cdu t4o chft
(ddnhcho: Cao hqc)
Thdi gian ldm bdi.' 180 phtit
CAuI
O tr4ng th6i ccybin, electron c6 nlng lugng cao nh6t cria c6c nguyOntt A vd B clugc d[c tnmg
boi c6c sOluqng tir sau:
A)
n:2
1: 1
m : - 1 t r r s= + l l 2
B)
n:2
l:1
m:*1
mr: -l/2
*ABz
vir
1) Dnng thuytit VB hay cho bi6t tr4ng th6i lai ho6 cira nguy€n tir A trong hai phdn ttr ABz,
dang hinh hgc cria c6c phdn tu d6.
2) Dung thuy6t MO hay so s6nh dO dai fiOn k6t vd n6ng lugng ion ho6 thu nhAt giira c6c phAn tu
Az vd AB.
Chu 2.
Nung n6ng h6n hqp gdm 46,0 gam 12vi 1,0 gam H2 trong mQt binh kfn o 470oC,xhy ra phin

7":9642
Ao.
Cho
bi6t
nang
s6ngco budcs6ng
Viet c6uhinh electronvd choUiettu tinh cuahai phrictr€n.
Ciu 6.
Khi hodtan 0,1mol NHI virom6t lugngnudcviradt, thu duoc 1 lft dungdichA c6 ndngd0 ion
M.
OH- bing 1,33.10-3
ll Xirc dinh pH cta dungdich A,
.
,
2l pH cuadungdlch thu clugcsaukhi th6m0,1 mol NaOH (bo quathOtfch NaOH r[n) vdo I lft
dungdich A bd.ngbaonhi€u?
3/ Tinh h6ngs0 phdnlibazo (Ks) cuaNHr.
C h od i e nt i c hh a tn h d n: L i : 3 , B e : 4 , 8 = 5 ,C : 6 , N : 7 , O : 8 , F : 9 , N e : 1 0 ,F e : 2 6 .
Ghi chri: Cdn b0 coi thi kh6ng giai th{chgi thAn.


e0 cno DUCvA DAo TAo
DArHec Huf

Hg ua t€n tht s'inh:
Sd bd,odanh:

xt rurr ruyiN srNH sAU DAr Hoc NAu zooz
M6n thi: cO sd r,f firuyfr noA noc v,q.c,{.u rao cn,{r
(d.d.nh

Hq ,-dt€n thi sinh:
SAnao danh;

DAI HOC HUE

KV THI TUYEN SINH SAU DATHQC NAM

2OO8

MOn thi: Co s6 Ij thuy€t hoti hgc vd Ciiu no chht
(ddnhcho Cao hoc)
Thdi gian ldm bdi: 180 phft
Cf,u I (1,5di€m):
Cho I mol H2 vi 1 mol 12viro m6t binh 30 lit dd hirt chAnkh6ne.dun n6Irsl€n 470"C.
1) Tinh 6p su6ttrong binh.
2) Tinh 6p sudtriOngcua 12vd HI trong h6n ho.pc6n bang.
Biet o 4J0oC,phan vngH2(k) + I.(k) : zHI(k) c6 hangsd c A nb d n gK : 5 0 .
Chu 2(1,0di€m):

c c6 nhi€td0 tl6ngddcla -0,23'C.
Khi hoatan0,85gamZnClztrong 725gamH2Oth\ dungdich nhin ilucr.
tl6ngcta nu6cld K6= 1,86.Chonguy€n
Tinhd6 di6nly a cia ZnCl2trongdungdichtrdn.nl6t trings6nghiQm
=
tu kholcualn 6) vdcuaL I J5.5.
Ciu 3(l .0 di€m):
O nhi€td6 913K, phin fng dehydroho6 metylamin:H3C-NHr&)-+ HCNft/ + ZHz&)
gtdy-1.
c6hing st5ttic d6 bing 5.1,0'3
1) Tinh thdi giannriaphin img 1172.

lT)l: *l

B

n:2

!:1,

filt:

*1

mr:

-

ms: -

1
2
1
2

1) Hey du tlorlLn
hoe tri t6i tla c6 thii c6 cta c6c nguy6n t6 A vd B.
2) Dirng thuydt MO, hly x5c dinh tu tinh cria phdntu Br.
3) A vir B t?o phentd ABr c6 ciu truc 1amgiricphing. ddu.Li€n k6t A-B c6 phiLncuc kh6ng?PhAnhr AB, co
phin cuc kh6ng? T4i sao?
Ciu 7(1,5 di€nt):
Cho hai phuc [Co(NH3)6]3'vd [CoF6]r-c6 ndng luong t6ch A" lAn luot liL275 kJhnol vdL155 kJ/mol. Ndng

3) NIu6nldrngiAmd0 tan criaPbIzdi 10 6n tht phdi th6mbaonhi6umol NaI vdo 1 lit dung
dicirbio hodFbIz?
Ciu lII. l.) Efnh nghiat6c dOphanrmg. Viiit bi6u thric toanhoc m6 ta t6c dOtrung binh vd t6c d0
tuc +!bi.
2) X6t phanrmg bdc mOtxAyra d nhiOtd0 I c6 th&i gian nriaphdnung benercOOgldy.
a) X6c dlnh hdngs6 t6c d0 phanring d nhiQtdg d6.
b) Tinh t"hdigian phan ring can *rltit d6 n6ng dOch6tphan ung giam 90% so vdi ban dAu.
C4.uIV. Tinh AGi* vd AS!r, criaphanung: 2lt(k) + Oz&) = 2HrO(l).
qo= 1,23V
ei6t: O2k) + 4* + 4e=2HzA0
Nniet tao thanhoia I{rO(/, ML, = -68,32kcal/mol.
Ciu V. Cho bi6t ph6 ph6t xp crianguyOntri hidro c6 )w = 1215Ao, Irr = 1025A', Lq : 92'l N
thuQcddyLyman.X6c dinh c6cbu6c s6ngls2 vd X+z6 ddyBalmer.
Ciu VI. Electronc6 ndnglugng caonh6t trong cduhinh electroncrianguydnt6 A duqc tl6ctrung
b d i c 6 c s 6l u g n g t t s a un: : 2 , ( . : l , m : + 1

na*,=-l.Nguy€nt6BcungchuklvdiAvdthu0c

nh6m IVA, nguydnt5 C ctrngnh6m vdi A vd thu0c chu lcj' 3.
1) X6t su tao thdrl cacphantt B& vd C& theo thuy6tVB.
2) Sc s6nhnhiOtdQho6 l6ng c0alJri BAz v6i khi CAr. Gi6i thich?
Ciu VII. xdt phfc [Cu(Nr]I)al2*.Hdy cho bi6t:
1) Trangrh6i lai ho6 criaCu2*trongphrlc.
2) CAutric hinh hqc vd tinh chdttu criaphric.
3) Su t6ch mrlc ndng luong d cria Cu2*trong trucmgphtii tr! cria phrtc tr6n.
Cco Ci$ntich hat nhtu: CUQ = 29);N(Z = 7); H(Z = l).

Ghi chir: Can b0 coi thi khdnggiai thfchgi th1m