Giíi h¹n_Qu¸ch Duy TuÊn
1)
1
352
lim
23
23
1
−+−
+−
→
xxx
xx
x
→ -2
2)
32
38
lim
2
1
−+
−+
→
xx
x
x
→1/24
3)
2
24

0
812
lim
−−+
→
→ 13/12
6)[§HSPHN_B00]
1
57
lim
2
3
1
−
−−+
→
x
xx
x
→ 7/12
7*)[§HTL_01]
2
3
0
3121
lim
x
xx
x
+−+

→
→ 1/75
10)[§HSPHNII_A99]
1
212
lim
5
4
1
−
−+−
→
x
xx
x
→7/10
11)[§HQG_A98]
1
23
lim
3
1
−
−−
→
x
xx
x
→ 3/2
12)

15)
2
0
2coscos1
lim
x
xx
x
−
→
→ 5/2
16)
2
0
2coscos4cos
lim
x
xxx
x
−
→
→ -11/2
17)
x
ee
bxax
x
−
→
0


→
π
→ π
20)[§HSP Vinh_B99]
xx
xx
x
2cos2sin1
2cos2sin1
lim
0
−+
−−
→
→ -1
21)
x
xx
x
sin
243
lim
0
−−+
→
→ -1/4
22*)[§HAN_00]
x
xxx

x
+++
−∞→
→ -1/2
25)[§HGT_95]
1
21
lim
3
1
−
−+
→
x
x
x
→3/2
2
,
3
x
=t
26)[HVNH_98]
1
12
lim
1
−
−−
→

→ -1/4
29)[§HSPV_01]
x
xxx
x
3
3
3
2
0
11
lim
+−++
→
→ 1/3
30)[§HHH_98]
xx
x
xtg
sin
1
2
0
)1(lim
+
→
→ e
31)[§HHH_99]
x
ee

0
+−+
→
→ 1
34)[§HSPHN_D00]
)1sin(
2
lim
3
1
+
++
−→
x
xx
x
→ 4
35)[§H§§_AV00]
xx
xx
x
+−−
+−−
→
11
11
lim
2
0
→ 1/2

−
→
→ 37/121
39)[§HSP2_A00]
a)
)
4
(.2lim
4
xtgxtg
x
−
→
π
π
→ 1/2
b)
2
0
cos3
lim
2
x
x
x
x
−
→
→ 1/2+ln3
( Thªm h»ng sè 1, sau ®ã ®Æt

−
→
Giíi h¹n_Qu¸ch Duy TuÊn
→ -1/12
42)[§HQGHN_A95]
2
2
0
4sinsin2sin
lim
x
xxx
x
−
→
→ 0
43)[§HGT_97]
x
x
x
1
coslim
0
→
→ 0
( Sö dông giíi h¹n kÑp -
x
x
xx
≤≤