Tran Sú Tuứng kim tra ẹaùi soỏ 10
CHNG VI: CUNG V GểC LNG GIC
KIM TRA 1 TIT
S 1
Phn I: Trc nghim khỏch quan (3 im, mi cõu 0.5 im)
Cõu 1: iu kin trong ng thc tan.cot = 1 l:
a)
k , k Z
2

+
b)
k , k Z
2


c)
k , k Z
d)
k2 , k Z
2

+
Cõu 2: Tớnh , bit cos = 0.
a)
k2 , k Z
2

= +
b)
k2 , k Z



+ d) tan R
Cõu 5: sin3xcos5x sin5xcos3x = ?
a) sin8x b) sin2x c) sin2x d) cos8x
Cõu 6: n gin biu thc
sina sin3a sin5a
P
cosa cos3a cos5a
+ +
=
+ +
. Chn li gii ỳng trong
cỏc li gii:
a)
sina sin3a sin5a sin9a sin
P tan
cosa cos3a cos5a cos9a cos
+ +
= = = =
+ +
b)
sina sin3a sin5a sin9a
P tan9a
cosa cos3a cos5a cos9a
+ +
= = =

2
a cos
2
3a.
Cõu 3: (2 im) Chng minh rng trong tam giỏc ABC, ta cú:
sin2A + sin2B + sin2C = 4sinAsinBsinC
=================
2
Tran Sú Tuứng kim tra ẹaùi soỏ 10
CHNG VI: CUNG V GểC LNG GIC
KIM TRA 1 TIT
S 2
I. PHN TRC NGHIM KHCH QUAN ( 4 im)
Cõu 1. Trờn ng trũn lung giỏc,
cho im M vi AM = 1 nh
hỡnh v di õy :
Hóy chn cõu ỳng :
a) sAM =
1 k2+
,
k Z
b) sAM =
1 k2 +
,
k
Z
c) sAM =
3
k2


5

d)
4
5

Cõu 3. Bit
4 2

< <
, hóy chn cõu ỳng :
a)
cot 0 <
b)
tan2 0 <
c)
cos3 0 >
d)
sin 4 0 >
Cõu 4. Hóy chn ng thc ỳng vi mi a :
a) cos2a = 1 2cos2a b) sina = 2 sin
a
2
.cos
a
2
c) sin4a = 4 sina . cosa d) sin2a =
1
2
sina . cosa

2 3
=
, tớnh cosa v sin2a . ( 2 im)
Cõu 3. Tớnh giỏ tr ca biu thc A = ( cos110
0
+ cos10
0
)
2
cos
2
50
0
. ( 2 im)
=================
3
AA
/
B
/
B
O
M
x
/

x
y
/
y

1 = 552
0
12
0
2 = 1125
0
45
0
3
=
35
2

2

Phn II: T lun (7)
Cõu 1: (3) Rỳt gn biu thc sau: A =
2 2
sin(a b)sin(a b)
cos a.cos b
+
Cõu 2: (4 ) Chng minh cỏc ng thc sau:
a)
2 2
1 sin2x tgx 1
tgx 1
sin x cos x
+ +
=


2a = 1 d) 1 + cot
2
a =
2
1
cos a
(cosa

0).
Cõu 2. Cho sina =
1
3
, vi 90
0
< a < 180
0
. Giỏ tr ca cosa l:
a)
2 2
3

b)
8
9
c)
2 2
3
d)
2
3

c)
6
5
d)
5
6
Cõu 6. Giỏ tr biu thc : A= sin
2 0 2 0
2 0
1
45 cot g 60
cos 135
+
bng
a)
7
6
b)
6
7
c)
7
6
d)
6
7
II. PHN T LUN (7 im)
Cõu 1. Cho cosa =
3
5

Cõu 4. Chng minh biu thc khụng ph thuc x, y:
A=
2
2 2 2 2
2
sin x
tg y cos x sin x tg y
cos y
+
===================
5