Giáo hóa học lớp 12 cơ bản - Tiết 54: HỢP KIM CỦA SẮT I. MỤC TIU:
1. Kiến thức: HS biết
- Thnh phần, tính chất v ứng dụng của gang, thp.
- Nguyn tắc v quy trình sản xuất gang, thp.
2. Kĩ năng: Giải cc bi tập liên quan đến gang, thép.
3. Thái độ:
II. CHUẨN BỊ: Đinh sắt, mẩu dây đồng, dung dịch HCl,
dung dịch NaOH, dung dịch FeCl
3
.
III. PHƯƠNG PHÁP: Đàm thoại + diễn giảng + thí
nghiệm trực quan.
IV. TIẾN TRÌNH BY DẠY:
1. Ổn định lớp: Cho hỏi, kiểm diện.
2. Kiểm tra bi cũ: Tính chất hoá học cơ bản của hợp chất
sắt (II) và sắt (III) là gì ? Dẫn ra các PTHH để minh hoạ.
3. Bi mới:
HOẠT ĐỘNG CỦA THẦY
VÀ TRỊ
NỘI DUNG KIẾN THỨC
Hoạt động 1
 GV đặt hệ thống câu hỏi:
- Gang l gì ?
I – GANG
1. Khi niệm: Gang là hợp kim của

 GV thông báo các quặng sắt
thường dung để sản xuất gang là:
hematit đỏ (Fe
2
O
3
), hematit nu
(Fe
2
O
3
.nH
2
O) v manhetit (Fe
3
O
4
).

b) Nguyn liệu: Quặng sắt oxit
(thường là hematit đỏ Fe
2
O
3
), than
cốc v chất chảy (CaCO
3
hoặc SiO
2
).

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