Giáo trình xác suất thông kê - Chương VI - Pdf 35

Ch ’u ’ong 6
L
´
Y THUY
´
ˆ
ET T

U

ONG QUAN V
`
A H
`
AM H
`
ˆ
OI QUI
1. M
´
ˆ
OI QUAN H
ˆ
E
.
GI
˜

UA HAI D
¯
A


ˆe c´o mˆo
.
t s
´
ˆo
quan hˆe
.
sau:
i) X v`a Y ¯dˆo
.
c lˆa
.
p v
´

oi nhau, t
´

uc l`a viˆe
.
c nhˆa
.
n gi´a tri
.
c

ua ¯da
.
i l


o
.
ng ng
˜
ˆau nhiˆen kia.
ii) X v`a Y c´o m
´
ˆoi phu
.
thuˆo
.
c h`am s
´
ˆo Y = ϕ(X).
iii) X v`a Y c´o s

u
.
phu
.
thuˆo
.
c t

u

ong quan v`a phu
.
thuˆo

* Moment t

u

ong quan (hiˆe
.
p ph

u

ong sai) c

ua hai ¯da
.
i l

u

o
.
ng ng
˜
ˆau nhiˆen X v`a Y, k´ı
hiˆe
.
u cov(X, Y ) hay µ
XY
, l`a s
´
ˆo ¯d

Thˆa
.
t vˆa
.
y, ta c´o
cov(XY ) = E{X.Y − X.E(Y ) − Y.E(X) + E(X).E(Y )
= E(XY ) − E(X).E(Y ) − E(X).E(Y ) + E(X).E(Y )
= E(XY ) − E(X).E(Y )
99
100 Ch ’u ’ong 6. L´y thuy
´
ˆet t

u

ong quan v`a h`am h
`
ˆoi qui
⊕ Nhˆa
.
n x´et 1
* N
´
ˆeu (X, Y ) r
`

oi ra
.
c th`ı
cov(X, Y ) =

n x´et
i) N
´
ˆeu X v`a Y l`a hai ¯da
.
i l

u

o
.
ng ng
˜
ˆau nhiˆen ¯dˆo
.
c lˆa
.
p th`ı ch´ung khˆong t

u

ong quan.
ii) Cov(X,X)=Var(X).
2.2 Hˆe
.
s
´
ˆo t

u

u r
XY
,
l`a s
´
ˆo ¯d

u

o
.
c x´ac ¯di
.
nh nh

u sau
r
XY
=
cov(X, Y )
S
X
.S
Y
v
´

oi S
x
, S


u

ong quan ¯do m
´

uc ¯dˆo
.
phu
.
thuˆo
.
c tuy
´
ˆen t´ınh gi
˜

ua X v`a Y . Khi |r
XY
| c`ang
g
`
ˆan 1 th`ı m
´
ˆoi quan hˆe
.
tuy
´
ˆen t´ınh c`ang ch
˘

´
ˆo t

u

ong quan
Lˆa
.
p m
˜
ˆau ng
˜
ˆau nhiˆen W
XY
= [(X
1
, Y
1
), (X
2
, Y
2
) . . . (X
n
, Y
n
)].
D
¯


R =
XY − X.Y
S
X
.S
Y
trong ¯d´o
X =
1
n
n

i=1
X
i
, Y =
1
n
n

i=1
Y
i
, XY =
1
n
n

i=1
X

´
ˆo t

u

ong quan 101
V
´

oi m
˜
ˆau cu
.
th

ˆe, ta t´ınh ¯d

u

o
.
c gi´a tri
.
c

ua R l`a
r
XY
=
xy − x.y

i
s
2
x
=
1
n
n

i=1
x
2
i
− (x)
2
, s
2
y
=
1
n
n

i=1
y
2
i
− (y)
2
Ta c´o

´
ˆat c

ua hˆe
.
s
´
ˆo t

u

ong quan
Hˆe
.
s
´
ˆo t

u

ong quan r =
xy − x.y
s
x
.s
y
¯d

u


´
ˆen t´ınh gi
˜

ua hai ¯da
.
i l

u

o
.
ng ng
˜
ˆau nhiˆen X v`a Y , n´o c´o c´ac t´ınh
ch
´
ˆat sau ¯dˆay:
i) |r| ≤ 1.
ii) N
´
ˆeu |r| = 1 th`ı X v`a Y c´o quan hˆe
.
tuy
´
ˆen t´ınh.
iii) N
´
ˆer |r| c`ang l
´


ua X v`a Y khˆong c´o phu
.
thuˆo
.
c tuy
´
ˆen t´ınh t

u

ong quan.
v) N
´
ˆeu r > 0 th`ı X v`a Y c´o t

u

ong quan thuˆa
.
n (X t
˘
ang th`ı Y t
˘
ang). N
´
ˆeu r < 0 th`ı
X v`a Y c´o t

u

nh hˆe
.
s
´
ˆo t

u

ong quan c

ua Y v`a
X
X 1 3 4 6 8 9 11 14
Y 1 2 4 4 5 7 8 9
Gi

ai
Ta lˆa
.
p b

ang sau
102 Ch ’u ’ong 6. L´y thuy
´
ˆet t

u

ong quan v`a h`am h
`

= 524

xy = 364

y
2
= 256
Hˆe
.
s
´
ˆo t

u

ong quan c

ua X v`a Y l`a
r
XY
=
n

xy − (

x)(

y)

n(

2.5 T

y s
´
ˆo t

u

ong quan
D
¯

ˆe ¯d´anh gi´a m
´

uc ¯dˆo
.
ch
˘
a
.
t ch

e c

ua s

u
.
phu

y
trong ¯d´o
s
y
=

1
n

n
i
.(y
x
i
− y)
2
; s
y
=

1
n

m
j
.(y
j
− y)
2
T

i khi Y v`a X phu
.
thuˆo
.
c h`am s
´
ˆo.
iv) η
Y/X
≥ |r|.
N
´
ˆeu η
Y/X
= |r| th`ı s

u
.
phu
.
thuˆo
.
c t

u

ong quan c

ua Y v`a X c´o da
.

u
`

ot ta c`on x´et
hˆe
.
s
´
ˆo x´ac ¯di
.
nh m
˜
ˆau β = r
2
v
´

oi r l`a hˆe
.
s
´
ˆo t

u

ong quan. Ta c´o 0 ≤ β ≤ 1.
3. H
`
ˆoi qui 103
3. H

ng c´o ¯di
`
ˆeu kiˆe
.
n c

ua ¯da
.
i l

u

o
.
ng ng
˜
ˆau nhiˆen r
`

oi ra
.
c Y v
´

oi ¯di
`
ˆeu kiˆe
.
n X = x l`a
E(Y/x) =

o
.
ng ng
˜
ˆau nhiˆen r
`

oi ra
.
c X v
´

oi ¯di
`
ˆeu kiˆe
.
n
Y = y l`a
E(X/y) =
n

i=1
x
i
P (X = x
i
, Y = y)
ii) D
¯
a

´

oi y khˆong ¯d

ˆoi
3.2 H`am h
`
ˆoi qui
* H`am h
`
ˆoi qui c

ua Y ¯d
´
ˆoi v
´

oi X l`a f(x) = E(Y/x).
* H`am h
`
ˆoi qui c

ua X ¯d
´
ˆoi v
´

oi Y l`a f(y) = E(X/y).
Trong th


oi nhau,
trong ¯d´o viˆe
.
c kh

ao s´at X th`ı d
˜
ˆe c`on kh

ao s´at Y th`ı kh´o h

on thˆa
.
m ch´ı khˆong th

ˆe kh

ao
s´at ¯d

u

o
.
c. Ng

u
`

oi ta mu


u bi
´
ˆet X, n
´
ˆeu d

u
.
¯do´an Y b
`
˘
ang ϕ(X) th`ı sai s
´
ˆo pha
.
m ph

ai l`a E[Y − ϕ(X)]
2
.
V
´
ˆan ¯d
`
ˆe ¯d

u

o

o nh
´
ˆat.
Thˆa
.
t vˆa
.
y, ta c´o
E[Y − ϕ(X)]
2
= E{([Y − E(Y/X)] + [E(Y/X) − ϕ(X)])
2
}
= E{[Y − E(Y/X)]
2
} + E{[E(Y/X) − ϕ(X)]
2
}
+2E{[Y − E(Y/X)][E(Y/X) − ϕ(X)]}


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