x2 7 x 6
x4 2008x 2 2007 x 2008
x 2 3x 2
8 x
1
x
2
x 1
4 x2
0
1
x2
2
4 x2
1
x2
x
1
x
hai c
can, m
c v
k
N
b
M
th
th nh
s
th nh
ph n
bao nhi u k .
nh
ph
t
v chia
tr
1c
m
k
,b
sao cho AD = BC. T
b
1
.
1 x
2
1 x2
cho m
ng
tr n c bao nhi u
v s d
s t nhi n n.
8
1 x8
t
m
s k .S
m
ng
nh sau:
th m
1
s k
11
trong ph n
k
v
l .
Cho tam gi
can c dung t
xu c
nh th
thi
t s ng v n
n3 n chia h cho 6 v
1 x
Nh n ng
l . C ti
th m
s g
ng l 16 v s d l m
nhau th
gi
L
-2009
c
l
nc
.
b
l . Sau khi b
k
v
vi n v m
A = 200. Tr n AB l
l
vi n nh
i
b)
c)
(
a) X4 + 6y2 -7 = 0
1
2011x 1
z
1
x
2
2014 2
2014 2
: (x2 8)2 + 36
ng minh :
l
am ts h ut.
ng th c sau :
1
a) Ch
2
b) Ch ng minh : AEF ~
= FK.FC.
c)
i.
12cm.
(4
2015 2
2015 2
a2 b2
b2 c2
2
nh nh t c a A =
6x 5 9x 2
a) Ch ng minh b
b)
: H Th Song
m i bi u th
2
b)
1969
1971
2
1
9 x 20
x
2
1
11x 30
x
2
1
13x 42
2 1970
(
I
c) Tam
x 2
2010
nh:
:(
a.
5: (7
b)
c)
3x
x2
27 3x2
:
1
x 3
)
2)
a)
1
2 zx
x 4
2008
1
z 2 xy
x 2010 x
2
1 1
x y
0
2
2x 6
x 3 27
3x 2 8x 6
x 2 2x 1
D = CB.CK
2
t
.
x2 1
2
5 x 1 2x
:
x 1 1 x2 x2 1
a
ab + a + 2
b1) n2 n + 2
1
b
2c
bc + b + 1 ac + 2c + 2
b2) n5 n + 2
a) C
Cho ABC
OA'
AH
OB'
BK
OC'
CI
1
3
y
1
3.
2 x
. Gi
a) (x + x)2 + 4(x2 + x) = 12
b
c) x 2 x 3 x 4 x 5
x y
2
2
y
3
0
2
2007 2006
2005 2004
(a2 + 1)(b2 + 1)(c2
A (1
:(
1
1
1
1
)(1
)(1
)...(1
)
2
2
2
x
( x 1)
( x 2)
( x 9) 2
)
P( x)
2x2 2x 3
x2 x 2
f(x) = x1994 + x1993 +1 cho g(x) = x2 1
:(
OA2
OB 2
8a 2
3
N
GV:
1)Cho
(6
):
:
P
2
3x
2
x 2y
x 2y
x 2y
3x
(4
x
x
2
:
1
3x 2
x
2
2 x 4004 3x 6022
24
20
1
5x 6
1
x 3
1
2013
b/ Cho
)
30x2 + 31x
30
(a - b)2012 + (b - c)2013 + (c - a)2014
(4
)
n
A = n + 4n - 20n - 48
36
8
7
6
A = n + 4n + 6n + 4n5 + n4
3
(5
2
)
16
n
3-2014
-
)
1 x3
1 x
1 x2
x :
1 x x 2 x3
2
1 .
3
)
Cho a b
2
b c
1
AB
1
CD
2
.
MN
COD=
20142
3-2014)
.
1
2.5
3
1
1
........
5.8
(3n 1)(3n 2)
+ 6n2 -19n
x2 2y2 -2xy +6y
2
x 3
2010
a
b
b2
+ 2013x2 + 2012x + 2013
x 4
2009
x 5
2008
x 6
2007
0
x2y + y2z + z2x +zx2 +yz2 + xy2 x3 y3 z3 > 0
)
KM
b/
KN
DM
DN
1
2. 8 x
x
: (4
(a+b+c)( 1
3.
a
2
1
b
x 1
4 x
1
)
c
2
1
x2
2.
3.
x 2 10 x 21 .
2008
AB .
GB
BC
HD
.
AH HC
-2014
a4
8a 3 14a 2
8a 15
10 n 18n 1
Khi ta
A= a
4
a/
1
CD
2
MN
SC 0 D
2009 2
0
-2014)
.
1
2.5
3
1
1
........
5.8
(3n 1)(3n 2)
+ 6n2 -19n
x2
3
2
x 3
2010
a
b
b2
+ 2013x2 + 2012x + 2013
x 4
2009
x 5
2008
x 6
2007
0
x2y + y2z + z2x +zx2 +yz2 + xy2 x3 y3 z3 > 0
)
KM
b/
KN
DM
DN
a/ x2 3x 2 x 1 0
1
b/ 8 x
x
2
4 x
2
:
1
x2
:
2
4 x
2
1
x2
1
x
x
x(1 x 2 )2
Cho A =
: (
1 x
1 x2
1 x3
x)(
1 x
a, Cho x+
x)
1
2
2
x
( x 10) 2
a
a, Cho a,b,c > 0, CMR:
1
ACM
MNP
A
a 1 a 3 a 5 a 7
x a x 10
B( x )
P
A
15
1
x4 3x3 ax b
x 2 3x 4
1
22
1
32
a 2 8a 12 a 2 8a 10
a 2 a 6 a 2 8a 10
x a x 10
x2
1
x m x n ;(m, n Z )
a 10 x 10a 1 x 2
m n a 10
m.n 10 a 1
mn 10m 10n 100 1
m(n 10) 10n 10) 1
m n x mn
1
a) Cho x 2
2xy 2y2
A
b c
b
c a
9
4
.
5
x6
3x 2
1 y4
a(b c) 2 (b c) b(c a) 2 (c a) c(a
1 1
a b
1
N
2
a 2bc b 2
M
x2
Cho bi
a th
sau ra th
s :
ng tr nh:
. Ch ng minh r ng:
u th c:
a. R t g n bi u th c A.
b. T nh gi tr c a A , Bi t x =
c. T m gi tr c a x A < 0.
d. T m c c gi tr nguy n c a x
.
A c gi tr nguy n.
C u 3. Cho h nh vu ng ABCD, M l m t i m tu
n
ch BD. K ME
MF AD.
a. Ch ng minh:
b. Ch ng minh ba
(6
b.
( x + 2)( x + 3)( x + 4)( x + 5) - 24
= (x2 + 7x + 11 - 1)( x2 + 7x + 11 + 1) - 24
= [(x2 + 7x + 11)2 - 1] - 24
= (x2 + 7x + 11)2 - 52
= (x2 + 7x + 6)( x2 + 7x + 16)
= (x + 1)(x + 6) )( x2 + 7x + 16)
<=>
(*)
(2
(2
a 3 4a 2 a 4
a 3 7a 2 14a 8
3.
P=(x-
x
A=
2
minh :
BC 2
a) BD.CE=
4
a) (1,5) a3 - 4a2 - a + 4 = a( a2 - 1 ) - 4(a2 - 1 ) =( a2 - 1)(a-4)
=(a-1)(a+1)(a-4)
0,5
=( a -2 )(a2 - 5a + 4) = (a-2)(a-1)(a-4)
0,5
a3 -7a2 + 14a - 8 =( a3 -8 ) - 7a( a-2 ) =( a -2 )(a2 + 2a + 4) - 7a( a-2 )
quay
(3
a) x2 4x + 4 = 25
b)
x 17
1990
x 21 x 1
1986 1004
0.
y z
xy
2
z 2xy
IM, IN
(AB BC CA) 2
AA' 2 BB' 2 CC' 2
c) 4x 12.2x +32 = 0
2x.2x 4.2x 8.2x
2x(2x 4) 8(2x 4) = 0 (2x 8)(2x
(2x 23)(2x 22) = 0 2x 23
x
2x = 2 3
= 22
1
x
1
y
1
z
0
xy
3
)
Cho a b
b c
2
2
g
)
(
c a
2
4. a 2 b2 c2 ab ac bc .
a b c.
)
a 4 2a3 3a 2 4a 5 .
-
x x2
(1 x)(1 x)
:
1 x
(1 x)(1 x x 2 ) x(1 x)
3
20092
ABCD.
B i 1:
Cho x =
a 2 (b c) 2
b2 c 2 a 2
;y=
(b c) 2 a 2
2bc
B i 2:
a,
1
1 1 1
ABC; AB = 3AC