ĐỀ ÔN 1
I. PHẦN CHUNG
Câu 1
x
y
x
+
=
−
C
!"!#
y x m= +
$%&&&'(&)*+,!&
-*,#&)./!
0&-1!23
Câu 24&&)'5!67
8
9
1! 1! 9: 8
1!
8 ; 9: 8
xy
y
x
=7'5!67>!&)
9 : ; 9 : ;
:
x m
x x x x
+
+ + − + + − − =
Câu 4a7'!&@*,+6!
( )
SA ABC⊥
+@A*,1!&>B!(C+
!&D!!&E&F'"!@,*,/!
α
=..G&'@*,H
α
=7
α
.%!&610I
b=6!F'"!23-<J+ !6K
( ) ( )
9 Lx y− + − =
MN''5!67 !"!#
&O>!23$%&&&*+,*,A8
Câu 5 PQ#5!<+J+RST
9x y z+ + =
=U
V
!&6SIW&>X
zyx
&F'"!
]+]`
=++−=+−+
zyxzyx
βα
MN''5!67Fa>@(6_#&b'<c0&&F
'"!T
Câu VI a.4&&'5!67>6!N''X
]9]8`
=−−+−+ iziziz
2. Theo chương trình nâng cao
Câu VI b9Y!&*,(%&'5!67%*,1<?J^99A]+'5!67%
*<^`J?98A]%,&O>&d[?eTJ&b'5!67%,
Y=6!GB!!&0&)23-<JR+& !"!#
9
=
=
−=
tz
y
tx
Câu Hướng dẫn Điểm Câu Hướng dẫn Điểm
Câu
1a
Câu
1b
^=ghAi
^=.jJk+MG!5&)>+
&Q6+&)N
^,,=
^g
^l=3!&&
2
( 4) 2 3 0x m x m+ − − − =
m&
!&)l=
⇔
2
28 0m m R
+ > ⇔ ∈
^42&*<
9
[<
9
^+,<
[<
^+0&
<
9
19 28m
< ≤
^
f7c!
^
3
2
1
V= . sin .(1 sin )
3 3
ABC
a
SA S
α α
= −
^PY
2
.(1 )y t t
= −
>J6f
<
A
2
2
G&
0
45
α
=
^g !6KZ9[+iA
^=b<
\8<^9A]
2 3x⇔ = ±
^Me)!&)1
4 4
2 3; ; 2 3;
2 3 2 3
+ −
÷ ÷
+ −
^g&8<
≠
]
^l=
3
cot 4 4 cot 4 3 0x x⇔ − − =
cot 4 1
1 13
cot 4
2
x
x
=
⇔
±
I
x
^
= −
3
4
I
^g
≥
8x
^l=
+
⇔ − + + − − =
8 3 8 3
6
x m
x x
^ob>
17x
≥
+l=6p
12 8x x m+ − =
l=!&)
17x ≥
⇔
77 100m≤ ≤
^ob>
8 17x
k
k
−
⇔ = ⇔ = −
+
^
(3; 1;2), (1;3; 1)
P d
n u= − = −
uur uur
4&&W#l1&
*9`[;[?L
^g !"!#ka7O>*
N
, ( 4;5;10)
P d
n u
= −
uur uur
1f=l
( ') :d⇒
15 28 9
4 5 10
x y z
− − +
= =
( )x y z+ + =
2
. . .
x y z
y z z x x y
y z z x x y
+ + + + +
÷
÷
+ + +
2 2 2
(2 2 2 )
x y z
x y z
y z z x x y
≤ + + + +
÷
+ + +
2 2 2
1
2 2
x y z x y z
y z z x x y
+ +
⇒ + + ≥ =