333 BÀI TOÁN TÍCH PHÂN LUYỆN THI ĐẠI HỌC

1/ Cho hàm số : f(x)= x.sinx+x
2
. Tìm nguyên hàm của hàm số g(x)= x.cosx
biết rằng nguyên hàm này triệt tiêu khi x=k
π
2/Định m để hàm số: F(x) = mx
3
+(3m+2)x
2
-4x+3 là một nguyên hàm của hàm số:
f(x) = 3x
2
+10x-4.
3/Tìm họ nguyên hàm của hàm số: f(x)= cos
3
x.sin8x.
TÍNH :
4/I =
4
2
6
(2cotg x 5)dx
π
π
+
∫

5/ I =
∫

π
+
∫

8 / I =
∫
−
3
6
π
π
(tgx-cotgx)
2
dx
9/I =
dxxxnsix )cos(2cos
44
2
0
+
∫
π

10/ I =
3
2
0
4sin x
dx
1 cosx

∫

15/ I =
2
3
0
sin x dx
π
∫

16/I =
2
0
1 cos x
dx
1 cosx
π
−
+
∫

17/I =
2
4
0
sin x dx
π
∫

18/I =

sin
1
π
π
x
dx
22/ I =
∫
4
0
6
cos
1
π
x
dx
23*/ I =
3
3
2
3
sin x sin x
cot gx dx
sin x
π
π
−
∫
24/I =
∫

27/I =
4
2
2
1
dx
x 16 x−
∫
28*/I =
6
2
2 3
1
dx
x x 9−
∫
29/I =
2
2 2
1
x 4 x dx
−
−
∫
30/I =
2
2 3
0
x (x 4) dx+
∫

x
1
x
0
e
dx
e 1
−
−
+
∫
35/I =
e
2
1
ln x
dx
x(ln x 1)+
∫
36/I =
7
3
3
0
x 1
dx
3x 1
+
+
∫

6
tg x cot g x 2dx
π
π
+ −
∫
42/I =
x
ln3
x 3
0
e
dx
(e 1)+
∫
43/I =
0
2x
3
1
x(e x 1)dx
−
+ +
∫
44/I =
2
6
3 5
0
1 cos x sin x.cos xdx

2
1
0
x
dx
(x 1) x 1+ +
∫
49/ I =
2
3
0
cos xdx
π
∫
50/I =
1
x
0
1
dx
e 4+
∫
51/I =
2
x
1
1
dx
1 e
−

∫
55/I =
ln3
x
0
1
dx
e 1+
∫
56/I =
2
3
1
1
dx
x 1 x+
∫
57/I =
1
2 3
0
(1 x ) dx−
∫
58*/I =
1
2x
0
1
dx
e 3+

dx
x 1
+
+
∫
63/I =
2
e
1
x 1
.ln xdx
x
+
∫
64*/I =
2
2
0
4 x dx+
∫
65/I =
e
2
1
(ln x) dx
∫
66/I =
1
0
1

70/I =
2
0
sin x.sin 2x.sin3xdx
π
∫
71/I =
2
4 4
0
cos2x(sin x cos x)dx
π
+
∫
72*/I =
2
3 3
0
( cos x sin x)dx
π
−
∫
73/I =
7
3
8 4
2
x
dx
1 x 2x+ −

π
+
∫
78/I =
e
1
cos(ln x)dx
π
∫
79/I =
2
1
x
dx
1 x 1+ −
∫
80/I =
e
1
1 3ln x ln x
dx
x
+
∫
81/I =
3
2
2
ln(x x)dx−
∫

86*/I =
3
2
2
1
dx
x 1−
∫
87/I =
6
2
0
x.sin xcos xdx
π
∫
88/I =
2x 2
0
e sin xdx
π
∫
89/I =
2
2
1
1
x ln(1 )dx
x
+
∫

∫
93/I =
3
0
sin x.ln(cosx)dx
π
∫
94/I =
2
e
2
1
cos (ln x)dx
π
∫
95/I =
2
e
e
ln x
dx
x
∫
96/I =
2
e
1
ln x
dx
ln x

101/I =
3
3
2
1
x
dx
x 16−
∫
102/I =
3
4
4
sin 2x dx
π
π
∫
103*/I =
2 x
1
2
0
x e
dx
(x 2)+
∫
104*/I =
4
1
x

108/I =
4
2
1
1
dx
x (x 1)+
∫
109/I =
1
3
0
4x
dx
(x 1)+
∫
110/I =
6
2
0
cos x
dx
6 5sin x sin x
π
− +
∫
111*/I =
2
e
2

+
∫
115/I =
0
cosx sin xdx
π
∫
116/I =
2
0
1 sin xdx
π
+
∫
117/I =
0
1 sin xdx
π
−
∫
118/I =
1
3
2
1
ln(x x 1) dx
−
 
+ +
 

2
2
1
5
dx
x 6x 9− +
∫
123/I =
1
2
5
1
dx
2x 8x 26
−
+ +
∫
124*/I =
0
2
2
sin 2x
dx
(2 sin x)
−π
+
∫
125/I =
1
2

1
dx
sin x 9cos x
π
π
−
+
∫
129/I =
2
2
cosx 1
dx
cos x 2
π
π
−
−
+
∫
130/I =
2
0
1 sin x
dx
1 3cos x
π
+
+
∫

2
1
1
dx
x 2x 9
−
+ +
∫
135/I =
2
2
1
4x x 5 dx
−
− +
∫
136/I =
2
2
2
2x 5
dx
x 4x 13
−
−
+ +
∫
137/I =
2x 2
0

142*/I =
4
3
0
1
dx
cos x
π
∫
143/I =
2
1
3 x
0
x e dx
∫
144/I =
2
4
0
sin 2x
dx
1 cos x
π
+
∫
145/I =
3
4
1

1
1
dx
4x x−
∫
150/I =
1
x
0
1
dx
3 e+
∫
151/I =
0
xsin xdx
π
∫
152/I =
1
0
cos x dx
∫
153/I =
1
0
sin x dx
∫
154/I =
e

158/I =
3
3
6
4sin x
dx
1 cos x
π
π
−
∫
159/I =
3
2
6
1
dx
cos x.sin x
π
π
∫
160/I =
3
0
sin x.tgxdx
π
∫
161/I =
1
4x 2x

cos x
dx
cos x sin x
π
+
∫
165/I =
1
0
3
dx
x 9 x+ −
∫
166/I =
2 2
0
x cos xdx
π
∫
167/I =
2
4
0
xsin x dx
π
∫
168/I =
2
4
0

1
x ln(1 )dx
x
+
∫
173/I =
2
3
cos x.ln(1 cos x)dx
π
π
−
∫
174/
2
2
sin x 3
0
e sin x cos xdx
π
∫
175/I=
2
4
0
sin 2x
dx
1 sin x
π
+

dx
sin x cos x
π
+
∫
180/I =
2
0
sin x.ln(1 cos x)dx
π
+
∫
181/I =
2
2
0
cos x.cos4x dx
π
∫
182/I =
1
2x x
0
1
dx
e e+
∫
183/I =
1
0

e
2
1
e
ln x
dx
(x 1)+
∫
188/I =
1
2
0
1 x
x ln dx
1 x
+
−
∫
189/I =
4
2
1
1
dx
x (x 1)+
∫
190/I
4
1
6

∫
194/I =
2
2
1
ln(1 x)
dx
x
+
∫
195/I =
2
0
sin 2x
dx
1 cosx
π
+
∫
196/I =
2
3
2
1
x 1
dx
x
+
∫
197/I =

0
x cos x sin x dx
π
∫
201/I =
4
3x
0
e sin 4xdx
π
∫
202/I =
2
4
0
sin 2x
dx
1 cos x
π
+
∫
203/I =
2
2
1
5
dx
x 6x 9− +
∫
204/I =

e
dx
e e
−
+
∫
208/I =
2
sin x
0
(e cos x)cos x dx
π
+
∫
209/I =
2
0
sin 2x.cos x
dx
1 cosx
π
+
∫
210/I =
2
0
sin 2x sin x
dx
1 3cos x
π

dx
cos x 1 cos x
π
π
+
∫
214/I =
x 2
1
2x
0
(1 e )
dx
1 e
+
+
∫
215/I =
3
2 3
0
x (1 x) dx−
∫
216/I =
3
2
2
0
sin x.cos x
dx

220/I =
4
2
1
1
dx
x (x 1)+
∫
221/I =
2
2 3
0
sin 2x(1 sin x) dx
π
+
∫
222/I =
4
2
7
1
dx
x x 9+
∫
223/I =
3 4
0
xsin xcos xdx
π
∫

2
3
2
cos x cosx cos xdx
π
π
−
−
∫
228/I =
1
2
0
x
dx
4 x−
∫
229/I =
1
4
2
2
0
x
dx
x 1−
∫
230/I =
2
2

ln 2
x
0
1 e
dx
1 e
−
+
∫
234/I =
1
0
x 1 x dx−
∫
235/I =
1
2
0
x 1dx+
∫
236/I =
2
3
0
x 1
dx
3x 2
+
+
∫

∫
240/I =
2
1
2
0
x
dx
4 x−
∫
241/I =
4
2
1
1
dx
(1 x)x+
∫
242/I =
2
0
sin x
dx
x
π
∫
243/I =
2
0
sin3x

2
2
0
cosx
dx
cos x 1
π
+
∫
248/I =
7
3
3
0
x 1
dx
3x 1
+
+
∫
249/I =
2
0
sin 2x sin x
dx
cos3x 1
π
+
+
∫

1 sin x
π
+
∫
254/I =
2
0
cos x
dx
7 cos2x
π
+
∫
255/I =
2
3
0
x 1
dx
3x 2
+
+
∫
256*/I =
3
4
cos x sin x
dx
3 sin 2x
π

+
∫
260/I =
3
2
0
cos x
dx
1 sin x
π
−
∫
261/I =
3
6
0
sin x sin x
dx
cos2x
π
+
∫
262/I =
2
3
1
dx
sin x 1 cos x
π
π

0
x ln(x 1)dx+
∫
267/I =
3
2
2
1
3x
dx
x 2x 1+ +
∫
268/I =
1
3 2
0
4x 1
dx
x 2x x 2
−
+ + +
∫
269/I =
1
2
2
1
2
1
dx

2
0
x.tg xdx
π
∫
274/I=
2
2 2
0
1
dx
(4 x )+
∫
275/I =
2
1
3
0
3x
dx
x 2+
∫
276/I =
2
3
6
0
sin x
dx
cos x

4
1
6
0
x 1
dx
x 1
+
+
∫
281/I =
1
3
0
x
dx
(2x 1)+
∫
282/I =
3
7
3
2
0
x
dx
1 x+
∫
283/I =
2

dx
cos x 1
π
+
∫
287/I =
2
2
0
sin x
dx
cos x 3
π
+
∫
288/I =
2
2
0
sin x cos x(1 cos x) dx
π
+
∫
289/I =
4 4
4
0
sin x cos x
dx
sin x cosx 1

x 2x 10x 1
dx
x 2x 9
+ + +
+ +
∫
293/I =
7
2
1
dx
2 x 1+ +
∫
294/I =
3
2
2
1
2
1
dx
x 1 x−
∫
295/I =
2
2
2
3
1
dx

3
4
6
1
dx
sin x cos x
π
π
∫
300/I =
2
0
1
dx
2cos x sin x 3
π
+ +
∫
301/I =
2
4
cos x sin x
dx
3 sin 2x
π
π
+
+
∫
302/I =

∫
306*/I =
2
0
sin x
dx
cos x sin x
π
+
∫
307/I =
4
2
4 4
0
sin x
dx
cos x sin x
π
+
∫
308*/I =
2
2
0
tgx
dx
1 ln (cosx)
π
−

∫
312*/Tìm x> 0 sao cho
2 t
x
2
0
t e
dt 1
(t 2)
=
+
∫
313/I =
4
3
0
tg x dx
π
∫
314*/I =
4
5
0
tg x dx
π
∫
315/I =
4
3
6

∫
319*/I =
2
x
sin x
dx
3 1
π
−π
+
∫
320/I =
2
0
1
dx
2 cos x
π
−
∫
321*/I =
1
3x 1
0
e dx
+
∫
322*/I =
2
1

6
cos2x
dx
1 cos 2x
π
π
−
∫
326*/I =
4
2
0
t gx 1
( ) dx
tgx 1
π
−
+
∫
327*/I =
1
3
1
2
x
dx
x 1+
∫
328*/I =
3

+
∫
331*/I =
4
0
ln(1 tgx)dx
π
+
∫
332*/I =
3
2
4
tan x
dx
cos x cos x 1
π
π
+
∫
333*/I =
1
2
0
3x 6x 1dx− + +
∫.