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Bài 3 :
Tóm tắt Giải
R1 = 600Ω
R2 = 900Ω
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Điện trở của mạch MN :
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b/Cường độ dòng điện qua mạch chính là
I = UMN : RMN = 220 : 377 = 0,583 (A)
Hiệu điện thế đặt trên mỗi đèn :
U1 = U2 = I . R12 = 0,583 .360 = 209,8 (V)
ĐS : a/ 377 Ω b/ 209,8 (V)
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