TÍNH TOÁN CÔNG NGHỆ VÀ THIẾT BỊ XỬ LÝ NƢỚC THẢI - Pdf 70













 

Ch CNSH 2  K50 43



. 
I. 
1. 




4. 
 












 :
V
L
=
  

  
2
18µ
, m/s [ 1  222 ]


:
V
L
: 








o
: , µ
o
= 10
-3
Ns/m
C
o
: 









, C
o
= 0.35 kg/m
3

µ = µ
o
( 1 + 2.5C
o
) = 10
-3
( 1 + 2.5 * 0.35 ) = 1.95 * 10

m/s





:












 

Ch CNSH 2  K50 44

t =



=
3.5
0.56  10

L
.
V
nt
=


< 56* 10
-5

F >
500
5610
5
243600
= 10.33 m
2


















:
V = F * H = 10.33 * 3.5 = 36 m
3










: V = 36 * 1.2 = 44 m
3









:


:
R: 





, %
t: 





, h
a, b: 







5










:
R =

+
=
2.16
0.0075+0.0142.16
= 57.2 %












:
SS
ra
= 350 * ( 1  0.572 ) = 150 mg/l









 c:
V
c
=



,m
3
/ngày [ 2  205 ]


:
G
c
: ng c

, kg/
G
c
= Q * R
SS
* SS = 500 * 57.2% * 350.10
-3
= 100 kg/ngày












 

Ch CNSH 2  K50 46

2. 


6. 
 






 m
3
/ 500
SS mg/l 150





4500 mg/l




= 0.08 mgVSS/mgBOD








, k
d
= 0.02 
-1




, K
s
= 80 mgBOD/l





:
1



= Y
  
0


+ 
0
 

, 
-1
1



= 0.08
3 1660
80+ 1660
- 0.02= 0.2







: 





, 
SF: 



, SF = 2  20 [ 1  393 ]






 





:



= Y *

0


 k
d
, ngay
-1
[ 2  74 ]
=
( 

  )
(
1


+ 

)
=
0.08( 1660400 )
4500(
1
30
+ 0.02 )
= 0.42 




1+ 


, kg/


:
Q: 





, m
3
/
Y: 

, = 0.08 /mgBOD
H: 





, 76 %
k
d
: 








:
P
b
=
5000.080.76 1660 10
3

1+0.0230

= 30.34 kg/











P
x

P
x
: 











, P
x
= 43.4 kg/
 trng hn h

n/m
3







1.021000
= 0.043 m
3











:
V
CH4
= a* Q* So* H * 10
-3
( 1 
1.42
1+ 



), m
3
/[ 1  818 ]







, kd = 0.02 ngay
-1


: 



, 

= 30 


: 



, mg/l














 

:
C
x
H
y
O
Z
N + O
2
C
5
H
7
NO
2
+ CO
2









/M


=


, ngay
-1



:


: BOD
5


, S
o
= 1660 mg/l
X: , X = 4500 mg/l
: 



, = 0.42 


1660500
210
= 3.95 kgBOD
5
/m
3

 /































5
50 mg/l.












= 3500 mg/l .
 



= 0.46, K
d
= 0.06/.



50 mg/l.
3.1. 












: 0.7* 50 = 35 mg/l.



5

5












:
1



= Y
  
0


+ 
0
 

, 
-1
















= SF


:

c
: 





, 



: 





, 
SF: 




 k
d
, ngay
-1
[ 2  74 ]

( 

  )
(
1


+ 

)
=
0.46( 40015)
3500(
1
9
+ 0.06 )
= 0.3 















5
:
Y
b
=

1+



=
0.46
1+0.069
= 0.3

















:
V
b
=



, m
3



:

























:
V
b
=
83
1.021000
= 0.08 m
3







m
N
=
58 10
6
14
113500 10
3
= 14.4 mg/l
3.3. 
T















= 3500 mg/

:
Q

=


=
3500
120003500
= 0.42

3.5. 







OC
0
=
(  )
1000
- 1.42P
b
, kg/[ 2  105 ]

.
OC
0
=
(  )







20
o
C , C
s
= 9.08 mg/l
C: 





, C = 2 mg/l.



















, OC
t
= 237.3 kgO
2
/
OU: 












, 

300mm, 
















2
/ m
3



f: 



, f = 1.5










3.7. 





/














/M


=












 

Ch CNSH 2  K50 53

/



















4. 



 2
8. 
 






 m
3
/ 710
BOD mg/l 15
N



mg/l 29.6
pH 7.2 4.1. 




o
=3500/ 0.7 = 5000 g/m
3

C
t
: 







, C
t
= 12000 g/m
3

V
l
: 









max
= 7 m/h
C
L
= 6000 g/m
3

K = 600
V
L
= 7 * e
 6000*600*10-6
= 0.19 m/h


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