CHƯƠNG 1: CÁC BÀI TOÁN VỀ HÀM SỐ
BÀI 1. PHƯƠNG PHÁP HÀM SỐ
I. TÍNH ĐƠN ĐIỆU, CỰC TRỊ HÀM SỐ, GIÁ TRỊ LỚN NHẤT & NHỎ NHẤT
CỦA HÀM SỐ
1.y=fxab⇔
( )
x x a b∀ < ∈
( ) ( )
f x f x<
2.y=fxab⇔
( )
x x a b∀ < ∈
( ) ( )
f x f x>
3.y=fxab⇔ƒ′x≥∀x∈abƒ′x=
∈ab
4.y=fxab⇔ƒ′x≤∀x∈abƒ′x=
∈ab
5.Cực trị hàm số: !"#
( )
k
x x f x
′
= ⇔
$%&
{ }
6 6
n
x a b
f x f x f x f a f b
∈
=
• 9y=fx2ab3:
[ ]
( ) ( )
[ ]
( ) ( )
6 8 67
x a b
x a b
f x f a f x f b
∈
∈
= =
• 9y=fx2ab3:
[ ]
( ) ( )
[ ]
( ) ( )
+*
( )
y v x=
2.9P-&QRS#:ux≥vx)!
Q=<!RST+*Q=
( )
y u x=
UVQW#0
<+*Q=
( )
y v x=
3.9P-&QRS#:ux≤vx)!
Q=<!RST+*Q=
( )
y u x=
UVQW%R*<+*Q=
( )
y v x=
4.9P-QRS#:ux=m)!<!
<-RXy=m+*
( )
y u x=
5.G@Lux≥m>∀x∈?⇔
( )
?
Bài 1. Y<!
( )
Zf x mx mx= + −
a.L:mQRS#:ƒx=Px∈283
b.L:m&QRS#:ƒx≤P>∀x∈28[3
c.L:m&QRS#:ƒx≥Px∈
[ ]
8Z−
Giải: a.G$QRS#:ƒx=5
( )
( )
( )
( )
Z Z
Z Z
f x mx mx m x x g x m
x x
x
= + − = ⇔ + = ⇔ = = =
+
+ −
\ƒx=Px∈283:
[ ]
( )
g x m x
x x
= ≥ ∀ ∈
+
[ ]
( )
8[
6
x
g x m
∈
⇔ ≥
^<
( )
( )
Z
g x
x
=
+ −
.#028[30_⇔
[ ]
( )
( )
8[
f9
x =
:&QRS#:#V!
Zm = ≥
0+gP
f9
(
]
8Zx∈
:G@L
⇔
( )
g x m≤
P
(
]
8Zx∈
(
]
( )
8Zx
Min g x m
∈
⇔ ≤
^<
( )
( )
Z
x
y = m
f9
[
)
8x∈ −
:
x x+ <
0G@L
( )
g x m⇔ ≥
P
[
)
8x∈ −
[
)
( )
8
Max g x m
−
⇔ ≥
L
( )
( )
( )
[ ]
8 Z 8
h
m
⇔ ∈ −∞ − +∞
U
Bài 2. L:m&QRS#:5
Z
Z
Z x mx
x
−
− + − <
P>∀x≥
Giải:G@L
( )
Z
Z [
Z Z mx x x m x f x x
x
x x
⇔ < − + ∀ ≥ ⇔ < − + = ∀ ≥
L
[
x x
m m m
+
+ − + − >
>
x∀ ∈ ¡
Giải: \`
x
t = >
:
( )
[
x x
m m m
+
+ − + − >
>
x∀ ∈ ¡
( ) ( )
( )
[ [ [ m t m t m t m t t t t⇔ + − + − > ∀ > ⇔ + + > + ∀ >
( )
[
_
#_⇔
( ) ( )
t
Max g t g m
≥
= = ≤
Bài 4. L:mQRS#:5
( )
h [x x x m x x+ + = − + −
P
Giải: \jcP
[x≤ ≤
G$@L
( )
h [
x x x
f x m
x x
+ +
⇔ = =
− + −
Chú ý:9W
( )
f x
′
h x
m+!._
( )
h x
>
+!d
⇒
( )
( )
( )
g x
f x
h x
=
dE_#
( )
f x m=
P
[ ]
( )
[ ]
( ) ( )
( )
[ ]
( )
8[
8[
87 8 [ h 8m f x f x f f
Z 8 g x x x h x x x= + − = + −
L
( ) ( )
( )
Z o 8 Z
g x x x x h x x x
x x
′ ′
= + > ∀ ≥ = + − + >
÷
−
^<
( )
g x >
+!d
x∀ ≥
8
( )
h x >
+!d0
( ) ( ) ( )
f x g x h x=
d
( ) ( )
[ o [ o
x
f x x x x
x x x x
− +
′
= − + + = − + = ⇔ =
÷
+ − + −
I;Q.0_#67
[ ]
( )
( )
[o
oMax f x f m
−
= = ≤
Cách 2.\`
( ) ( )
( ) ( )
[ o
[ o h
x x
Z o ] Z x x x x m m
+ + − − + − ≤ − +
>
[ ]
Zox∀ ∈ −
Giải:
\`
Z o t x x= + + − >
⇒
( )
( ) ( )
Z o p Z ot x x x x= + + − = + + −
⇒
( ) ( ) ( ) ( )
p p Z o p Z o ]t x x x x≤ = + + − ≤ + + + − =
( ) ( )
( )
] Z Z o p 8 Z8Z
x x x x t t
⇒ + − = + − = − ∈
ab
$QRS#:
[
Z
x x
m
x x
− −
⇔ − + =
+ +
\`
[
)
[
[
x
u
x x
−
= = − ∈
+ +
4
( )
o x x m x⇔ − + = −
( )
( )
( )
Z Z
o Z q 7 o Zx x x m x x x m⇔ − + − − = ⇔ = = + − =
_
( )
g x m⇔ =
>Pc<.
( )
8+∞
L;+;_5
( ) ( )
Z [ g x x x x
′
= + > ∀ >
^<
( )
g x
!
( )
g x
)01+!
( )
( )
8 )
x
( )
Z Z
[ [
8o
o
o
f x x
x x
x x
′
= − + − ∈
÷
÷
−
−
\`
( )
( ) ( )
( )
( )
Z Z
[ [
8 o
o
o
f x x
f x x
f
′
> ∀ ∈
′
⇒ < ∀ ∈
′
=
9:GGL@LPQeP
⇔
[
o o Z om+ ≤ < +
Bài 11. (Đề TSĐH khối D, 2007):
L:mPQRS#:P
Z Z
Z Z
h
h
x y
x y
x y m
8 u x x x v y y
x x x y y
= + = + ≥ = = + ≥ =
4P#V!
( )
Z Z
h
h
]
Z h
u v
u v
uv m
u v u v m
+ =
+ =
⇔
= −
+ − + = −
⇔
u v
)!P-QRS#:;
( )
+
( )
f t
f
∞
u[
f
∞
9:.0PP
u
[
m⇔ ≤ ≤ ∨ ≥
Bài 12.(Đề 1I.2 Bộ đề TSĐH 1987-2001):
L:x&QRS#:
( )
< x x y y+ + + ≥
>+*
y∀ ∈ ¡
Giải: \`
< u y y
= + ∈ −
G@L
≥
( )
( )
g x x x
x x x
g
− ≥ − + ≥ ≥ +
⇔ ⇔ ⇔
+ + ≥ ≤ −
≥
Bài 13.Y<
Z
≤ = ≤ = −
9R
( )
y f u=
)!<X+*
( )
8 Z
[
u a
∈ −
L
( )
(
)
( )
(
)
( ) ( )
Z
o h 8 Z
+ + =
YT#U5
u
u
ab bc ca abc+ + − ≤
Giải:
( ) ( ) ( ) ( ) ( ) ( ) ( )
a b c a bc a a a bc a a a u f u+ + − = − + − = − + − =
\
( ) ( ) ( )
y f u a u a a= = − + −
+*
(
)
( )
[
a
b c
u bc
−
u u
[ [ u [ Z Z u
f a a a a a− = − + + = − + − ≤
^<
( )
y f u=
)!<X+*
( )
8
[
u a
∈ −
+!
( )
u
u
f <
8
( )
(
)
[ ]
a∈
0
( ) ( )
( )
{ }
67 8 f a f f≤
L
( ) ( ) ( )
( )
( )
[ ]
[ [8 [ [ [ f b c f bc f a a b c= − − − ≤ = − ≤ ⇒ ≤ ∀ ∈
Bài 16. Y6M5
( ) ( ) ( ) ( )
[ ]
a b c d a b c d a b c d− − − − + + + + ≥ ∀ ∈
Giải: G%k&XT+j!;&a, b, c, d, 5
( ) ( ) ( ) ( )
[ ]
( ) ( ) ( )
[ ]
f a b c d a b c d b c d a b c d
= − − − − + − − − + + + ≥ ∀ ∈
\
( )
[ ]
y f a a= ∀ ∈
)!<X0
[ ]
g b Min g g
∈
=
L
( )
( ) ( ) ( )
8 g c d g c d c d cd
= + + ≥ = − − + + = + ≥
⇒
( ) ( )
[ ]
f g b b= ≥ ∀ ∈
q;_
( )
f a ≥
_Q
BÀI 2. TÍNH ĐƠN ĐIỆU CỦA HÀM SỐ
A. TÓM TẮT LÝ THUYẾT.
1.y=fxab⇔ƒ′x≥∀x∈abƒ′x=
∈ab
2.y=fxab⇔ƒ′x≤∀x∈abƒ′x=
∈ab
Chú ý: L#<RS#:Q$gc/%11. 2.<(!v_w,
jcPƒ′x=∈ab
CÁC BÀI TẬP MẪU MINH HỌA
Bài 1. L:m
( ) ( )
o h Z
u
u x m x
x x
−
= ≥ ∀ ≥
+
( )
6
x
u x m
≥
⇔ ≥
L5
( )
( )
u
x
u x x
x x
+
′
= > ∀ ≥
+
^<
( )
y x
′
)01x=+!x=Z0⇔y′≥∀x∈2Z3
⇔
( )
[ ]
Z Zm x x x x+ ≥ + − ∀ ∈
⇔
( )
[ ]
Z
Z
x x
g x m x
x
+ −
= ≤ ∀ ∈
+
[ ]
( )
Z
67
x
Bài 3. L:m
( ) ( )
Z
Z
Z Z
m
y x m x m x= − − + − +
#0
[
)
+∞
Giải: !d
[
)
+∞
⇔
( ) ( )
Z y mx m x m x
′
= − − + − ≥ ∀ ≥
⇔
( )
o m x x x
− + ≥ − + ∀ ≥
Z o
Z o
x x
x x
= = −
⇔
= = +
8
( )
)
x
g x
→∞
=
LxGGL⇒
( )
( )
67
Z
x
g x g m
≥
u
[
m
= − + >
0
y
′
=
P
x x<
G@Lgx≥SjP')!5
L
( )
y x
′
≥
>
x∀ ≥
⇔
[
)
G+∞ ⊂
( )
( )
Bài 5. L:m
( )
x m x m
y
x m
+ − + +
=
−
#0
( )
+∞
Giải: !#0
( )
+∞
⇔
( )
[
x mx m m
y x
x m
− + − −
′
= ≥ ∀ >
−
∆ = + ≥
_#gx=P
x x≤
G@Lgx≥SjP')!5
Lgx≥>∀x∈+∞⇔
( )
G+∞ ⊂
( )
( )
o Z
Z
Z
m
m
x x g m m m
m
S
m
′
≤
≤ ∆ ≥
( )
( )
o
Z
6
Z
Z
x
g m m
m
g x
m
m
m
m
m
≥
= − + ≥
≤ −
≥
8y g u u= ∈ −
)!<X0_
( )
( )
o ]
[
Z
g m
m
g m
− = − ≤
⇔ ⇔ ≤ ≤
= − + ≤
Bài 7. L:m!
Z
[ p
y mx x x x= + + +
d+*r
x∈ ¡
Giải: i0=!<(
< < <Z
Z
[ ]
( )
( )
h
67
o
x
g u g m
∈ −
= − = ≤
Bài 8. Y<!
( ) ( ) ( )
Z
Z
Z
y m x m x m x m= + + − − + +
L:mc<.-!%!U[
Giải. ab
( ) ( ) ( )
Z y m x m x m
′
= + + − − + =
^<
u Z m m
[ [ Z
o [
m m
x x x x x x
m
m
− +
= − = + − = +
+
+
( ) ( ) ( ) ( )
[ Z m m m m⇔ + = − + + +
u o
Z u
o
m m m
±
⇔ − − = ⇔ =
cnQ+*
m + >
_#
u o
o
m
+
Z
−∞
6`c(f −=0QRS#:fx=P%_&x=−
Bài 2. '.QRS#:5
h Z ]x x x+ = − + +
Giải. G&QRS#:⇔
( )
Z ] hf x x x x= − + + − +
=
f9
Z
x ≤
:fxz⇒+gP
f9
Z
x >
:
( )
Z h
[
h u u h Z uf x x x x x= + + − + − + −
L5
( )
( ) ( )
Z [
h
Z
[
h u Z
h Z u
Z h u [ u h
f x
x
x
x x
′
= + + + >
+
× −
× − × −
⇒fx#0
)
h
u
x x x x
f x x x x g x
⇔ = + + + − − − = − + − + =
Lfx+!g′x=−ox
+x−uz∀x⇒gx
9P-fx=gx)!<!<-
( ) ( )
+!y f x y g x= =
^<fxd8gx.+!
( ) ( )
Zf g= =
0{P%_&x=
Bài 5. L:m67
( )
< < m x x x x x x
+ + ≤ + + + ∀
{
Giải. \`
( )
< < t x x t x x x= + ≥ ⇒ = + = +
⇒
t≤ ≤
⇒
t≤ ≤
c{
≥
^<
( )
( )
t t
f t
t
+
′
= >
+
0ft
⇒
( )
( )
Z
6
t
f u u= +
L
( )
] )
u
f u u
′
= + >
E_#
( )
f u
{
( ) ( )
< < < f x f x x x x⇔ = ⇔ = ⇔ =
[
k
x k
π π
⇔ = + ∈ ¢
Bài 7. L:
( )
x y∈ π
,tP
< <
Z h
x y x y
x y
4
( )
( )
[
Z h
f x f y
x y
x y
=
π
⇔ = =
+ = π
Bài 8. '.PQRS#:
Z
Z
Z
x y y y
y z z z
z x x x
+ = + +
+ = + +
Z
x x
x x
+ − <
− + >
Giải.
Z
Z
x x x+ − < ⇔ − < <
\`
( )
Z
Z f x x x= − +
L5
( ) ( ) ( )
Z f x x x
′
= − + <
⇒
( )
f x
.+!
( )
L
( )
<
|
x
f x x
′
= − +
⇒
( )
f x x x
′′
= −
⇒
( )
< f x x
′′′
= − ≥
∀xm
⇒
( )
f x
′′
2f∞⇒
( ) ( )
f x f
′′ ′′
> =
∀xm
[| |
x x
x− + −
⇒g′′x}
Z
Z|
x
x x− +
}fxm∀xm
⇒g′x2f∞⇒g′xmg′}∀xm
⇒gx2f∞⇒gxmg}∀xm⇒Q
Bài 2.YT#U5
x
x x
π
> ∀ ∈
÷
π
Giải.
x x
x f x
x
⇒gx.#0
π
÷
⇒gxzg}
⇒
( )
g x
f x
x
′
= <
∀x∈
π
÷
⇒f x.#0
π
>
−
∀xmym
Giải. ^<xmym)xm)y⇔)x−)ym0$&XT
⇔
) ) )
x
x y yx
x y
x
x y y
y
−
−
− > × ⇔ > ×
+
+
⇔
)
t
t
t
−
> ×
+
+*
′
= − = >
+ +
∀tm
⇒ft2f∞⇒ftmf}∀tm⇒Q
Bài 4.YT#U5
) ) [
y x
y x y x
− >
÷
− − −
( )
x y
x y
∀ ∈
≠
Giải. abc.de_5
f9ymx:⇔
y x
y x
y x
− < −
− −
ab!`#Rft}
) [
t
t
t
−
−
+*t∈
L
( )
( )
[
t
f t
t t t t
−
′
= − = >
− −
∀t∈⇒ft
⇒fymfxymx+!fyzfxyzx ⇒Q
= ≤ =
⇒fx2~f∞
⇒fazfb⇔
) )a b
a b
<
⇔a
b
zb
a
Bài 6. (Đề TSĐH khối D, 2007)
YT#U
( ) ( )
b a
a b
a b
a b+ ≤ + ∀ ≥ >
Giải. G$&XT
( ) ( )
[ [
b a
b a
a b
a b
( ) ( )
( )
[ ) [ [ ) [
[
x x x x
x
f x
x
− + +
′
= <
+
( )
f x⇒
.#0
( )
( ) ( )
f a f b+∞ ⇒ ≤
Bài 7. (Bất đẳng thức Nesbitt)
YT#U5
Z
a b c
b c c a a b
+ + ≥
+ + +
∀abm
Giải. 4g&W$v(./a≥b≥\`x}a⇒x≥b≥m
\`x}b⇒x≥m7b!gx}
x c
x c
+
+
+*x≥m
⇒
( )
c
g x
x c
′
= >
+
∀m⇒gx2f∞⇒
Z
g x g c
≥ =
Z
LxZ_#
Z
a b c
b c c a a b
+ + ≥
+ + +
−oxyf]x−]yf
Giải. G$T%R*%
Pxy}x−Zyf[
fy−
fZ≥Z
Lx_#6@xy}Z⇔
Z [
y y
x y x
− = =
⇔
− + = = −
Bài 2.
Y<xymL:(#,&-5S}
[
[
[ [
y y y
x x x
y x
y x y x
+ − − + +
x
y x y x
y x
= − + − + − + + − +
÷
÷ ÷
÷
S
y y x yx
x
y x xy
y x
−
p
< < < < < <
[ [
x y x y x y x y x y x y
= − + − − + = − + + − + +
S
p p
< <
[ [ [
x y x y x y
= − − + + − − ≤
q*
Z
x y k
π
= = + π k∈:
p
67
[
Z u ] p
x x x x x x x x x= = = = =
:
[
6
p
S = −
Bài 5.Y<
x y z ∈ ¡
L:(#,&-T5
E}px
fh[y
foz
−oxz−[yfZoxy
Giải. G$E⇔fx}px
−]z−]yxfh[y
foz
−[y
L∆′
x
}gy}]z−]y
−h[y
Giải aby}⇒x
}Z⇒E}Z)!(#-!
aby≠c$T%R*%e_
( )
Z
x y x y
x xy yS t t
u u
x xy y x y x y t t
− +
− + − +
= = = = =
+ + + + + +
+*
x
t
y
=
⇔ut
ftf}t
Z
u =
⇔t}⇒
Z
x y
x y
x xy y
=
⇔ = = ±
+ + =
67E}p⇔67u}Z⇔t}−⇒
Z Z
Z
Z Z
x y
x y
x xy y
x y
= −
( ) ( )
Z [x y x y x+ − + + =−
^<−[x
≤0
( ) ( )
Z x y x y
+ − + + ≤
⇔
Z h Z h
x y
− +
≤ + ≤
q*x}y}
Z h
−
±
:
Z h
6
x y
}
[ x x x+ + +
⇔
[ [ y x x x y y x x x x− = + + ⇒ − + = + +
⇔gx
}
Z x y x y+ + + − =
Lgx}Px
⇔∆′}
Z y y y y+ − − = + −
}
y y+ − ≥
^<y
}
( )
( )
h [ 8 7 [ 5
h [ 8 [ 5
x m x x P
f x
x m x x P
+ − + ≤ ∨ ≥
=
− + + − ≤ ≤
'rP)!-y}fx⇒P}P
∪P
cP#<(:%
e_
Hoành độ của các điểm đặc biệt trong đồ thị (P):
<!<P
P
f m
− ≤ ≤
= >
= >
⇔zm≤Z
9x
C
∉2x
A
x
B
3⇔m∉2−ZZ3:6fx}
( )
h
C
m
f x f
−
=
÷
Bài 10. (Đề thi TSĐH 2005 khối A)
Y<
x y z >
8
[
x y z
+ + =
L:6-E
x y z x y z x y z
= + +
+ + + + + +
Giải:E/%1&XTYg<(a, b, c, d > 5
( )
(
)
[
[
o
[ [ oa b c d abcd
a b c d abcd a b c d a b c d
+ + + + + + ≥ = ⇒ + + + ≥
+ + +
o o
o o
+ + + + + +
•
G
Y
P
P
•
G
Y
P
P
•
G
Y
P
P
Bài 11. (Đề thi TSĐH 2007 khối B)
Y<
x y z >
L:6-E
y
÷
Bài 12.
Y<
x y
x y
>
+ =
L:(#,&-S}
yx
x y
+
− −
Giải:
( ) ( ) ( )
yx
S y x x y x y x y x y
y x
≥
[
xy x y
≥ =
+
⇒
S ≥
⇒6S}
Bài 13.
Y<xy‚mL:67-5S}
( )
( )
xyz x y z x y z
x y z xy yz zx
+ + + + +
+ + + +
Giải: E/%1&XTCôsi +!BunhiaCôpski Z((5
Z
Zx y z x y z+ + ≥ ×
8
L:(#)*&,&-!
[y x x= + −
Cách 1: L;Q7(
[ ]
8D = −
8
8 [
[
x
y y x x
x
′ ′
= − = ⇔ = −
−
[
x
x
x x
≥
⇔ ⇔ =
[
y u u u
π
= + = + ∈ −
8
7 8 y y= = −
Bài 15. (Đề dự bị TSĐH 2003 khối B)
L:(#)*&,&-
( )
Z
o
[ y x x= + −
#0<
[ ]
8−
Cách 1.\`
[ ]
8u x= ∈
L
( )
Z
Z Z
[ Z [y u u u u u= + − = − + − +
[ ]
Z
o o
Z
] ] ] ]
[
Z
u u u u Z
[ [ [ [ [
[< Z [< <
u u u u Z
u u u
u u u
+ + ≥ × × × =
+ + ≥ × × × =
( )
o o
]
[ [ [
[ < <
p Z Z p
y u u u u y= + + ≥ + = ⇒ ≥
q*
[
x
y x y
x x
−
′
= = ⇔ = ⇒ =
+ +
( ) ( )
Z Z
) ) ) )
x x x x
x x x x
x
y
x
x
x
x
→∞ →∞ →∞ →∞
+ +
= = =
+
+
5 Z
5 Z
5 Z
x a a a
x b b b
x c c c
= + ≤ +
= + ≤ +
= + ≤ +
( )
p a b c a b c
+ + + ≤ + + + + +
⇔
a b c
≤ + + + + +
Cách 2. L#0`QXr„7_`
( ) ( ) ( )
8 8 8 8 8OA a AB b BC c= = =
uur uuur uuur
q*
x y= =
:67A=
+
2. L:MinA:ab#RnQe_
…Trường hợp 159
xy ≥
7bc.d5
xZ y′f −
y
−
a
a+ba+b+c
C
A
B
Z
O x
y
f9
x y≥ ≥
:•m⇒
6 A >
( )
( )
( )
A x y xy x y y x xy x y xy x y xy
= + + + + + + = + + + + + +
=
t t t
t t
− − −
+ × + × + +
( )
t
t
−
= + + +
⇔
( )
( ) ( )
f t
′
⇒
( )
( )
( )
p Z
8
u
f t f t
−
= =
9:.0_#5
( ) ( )
A f t A f t≤ ⇒ ≥ −
_#
( )
( )
p Z
6
u
A f t
−
= − = − < −
7._#⇔
( )
p Z
6
u
A
−
= −
Bài 18.Y<
[ ]
x y z ∈
<.tjcP5
Z
x y z+ + =
L:676-T5
( )
<S x y z= + +
Giải. ^<
[ ]
x y z ∈
0
Z
x y z x y z
π
:67E}
Z
<
[
2. L:MinS _:Max
( )
x y z+ +
Cách 1: Phương pháp tam thức bậc hai:
4g&W$v(./
{ }
8
z Max x y z z
= ⇒ ∈
G$+!((R+j
T;‚
( )
(
)
( )
Z p
<
[
Cách 2: Phương pháp hình học
abPr\j(+g„7_‚L;QnQ(
( )
M x y z
<.tjcP
[ ]
x y z ∈
U#<:);QQRS•GY^•′G′Y′„+*•8G8Y
8^8•′8G′8Y′
6`c(%<
Z
x y z+ + =
0
( )
M x y z
U#0`QX@5
Z
x y z+ + =
q;_;QnQ(
( )
M x y z
<.tjcP.U#0%Pƒ?‡4I9+*
(ƒ?‡4I9)!#(:);QQRS'r„′)!:-„)0
ƒ?‡4I9:„′)!e-:);QQRS+!ˆ)!e-)1(jƒ?‡4I9L„′6
)!:-„6)0ƒ?‡4I9^<„6
[
Bài 19. Y<
a,b,c 0
>
,tjcP
3
a b c
2
+ + ≤
L:(#,&-
S a b c
b c a
= + + + + +
Giải. Sai lầm thường gặp:
Z
o
Z ZS a b c a b c
b c a b c a
≥ + × + × + = + + +
÷ ÷ ÷
„
ƒ
4
Z
‡
6
z
x
?
I
9
Z
„′
a b c
= = =
⇒
[
[
a b c
a b c
u u u
u u u
o Z o Z o Z ] o ] o ] o
u u u u
o o o o o o
a b c a b c
b c a b c a
≥ × + × + × = + +
Z
u u u u
] o ] o ] o ] h h h
u Z Z u
o o o o
a b c
b c a a b c
≥ × × × =
(
)
u
h h
u
Z u Z u Z u
[
[
u u
[
[
u u
[
[
u u
a a a
b
b b
b b b
c
c c
c c c
a
a a
+ = × + + ≥ × +
÷ ÷
= × + + + + + + + +
÷
o Z
Z
h [h
o Z Z
[ [ [ [ [
u u
abc
a b c a b c
abc
≥ × × × × + × × × = + ×
÷
÷
[h [h Z u
Z Z
[ [
u u
Z
a b c
uur uur uuur
^<
u v w u v w+ + ≥ + +
uur uur uuur uur uur uuur
0_#5
( )
S a b c a b c
a b c
b c a
= + + + + + ≥ + + + + +
÷
=
( )
h
o o
a b c
a b c a b c
+ + + + + + + +
÷ ÷
a b c
abc
× × × × × × + ×
≥
(
)
p Zh
o
Z
a b c
+ ×
+ +
≥
p Zh ] Zh hZ Z u
[
o [ [ [
+ × = + = =
q*
a b c= = =
:
Z u
6
S =
B. CÁC ỨNG DỤNG GTLN, GTNN CỦA HÀM SỐ
I. ỨNG DỤNG TRONG PHƯƠNG TRÌNH, BẤT PHƯƠNG TRÌNH
⇒@RS#:
( )
[ [
[ f x x x= − + − =
P%_&x=Z
Bài 2. '.QRS#:5
Z h o
x x
x+ = +
Giải. @L ⇔
( )
Z h o
x x
f x x= + − − =
L5
( )
Z ) Z h ) h o
x x
f x
′
= + −
⇒
( ) ( ) ( )
Z ) Z h ) h
x x
f x
′′
= + >
x =
Bài 3. L:mG@L5
pm x x m+ < +
P>
x∀ ∈ ¡
Giải.
pm x x m+ < +
⇔
( )
p m x x+ − <
⇔
( )
p
x
m f x
x
< =
+ −
L5
( )
( )
p p
p p
x x
f x
x
x
→−∞ →−∞
− −
= =
+ +
9:GGL
( )
f x m>
x∀ ∈ ¡
⇔
( ) ( )
Z Z
6 o
[ [
x
f x f m m
∈
−
= − = − > ⇔ <
¡
x−∞x
⇒
[ [
x −π π
∈
0`
[ ]
x
t = ∈ −
⇒
<
t
x
t
−
=
+
8
L5
( )
( )
( )
8 f t t t t t t
′
= + − − = ⇔ = = −
⇒G.0
9:.0_#5
\P
[ ]
t ∈ −
:
[ ]
( )
[ ]
( )
6 67
t
t
f t m f t
∈ −
∈ −
≤ ≤
P
Giải. ⇔
( )
Z
Z
[
x
f x x x x m m
≤ ≤
= − − ≥ −
L5
( )
[
)
(
]
Z [ [ 8
Z [ [ 8Z
x x x
f x
x x x
∈
≥ −
⇔
[ m m− ≤
⇔−Z≤m≤u
Bài 6. L:m≥P5
Z
Zh
< o
[
ZZ
< o
[
x y m m m
x y m m
= − − +
= − +
P
Giải
⇔
Z
ab
( )
Z
uf m m m= − +
L5
( )
Z f m m m
′
= − = ⇔ = >
9:GGL_#5ƒm≥ƒ=∀m≥
cnQ+*
( )
x y+ ≤
_#P
P:m=cP#V!5
( )
( )
x y
x y
+ =
x∀ ∈ ¡
L5
( )
( )
) f x x x x
′
= + + = ⇔ =
⇒G.0
9:.0_#5
( ) ( )
f x f≥ =
⇒Q
Bài 2. Y<
a b c
a b c
>
+ + =
Y6M5T=
Z
Z
f x x x
′
= − = ⇔ = >
9:.0⇒
( )
Z Z
f x x≤ ∀ >
45
( ) ( ) ( )
( )
Z Z Z Z
a b c
T a b c
f a f f c
= + + ≥ + + =
\XT7._#
Z
a b c⇔ = = =
( )
( )
| |
|
| |
|
n n
n n
x x x
u x x u x
n
n
x x x
v x x v x
n
n
−
−
′
= + + + + = −
−
( )
[
| | [|
|
n n
x x x x
n
n
−
−
= + + + +
−
^<Z≤n)Š0ƒ′x‰%&+*−x
9:.0_#5
x−∞+∞f′−+
f
x−∞+∞f′+−
f
x−∞+∞f′+−
f
( ) ( )
f x f x< = ∀ ≠
⇒Q
Bài 4.YT#U5
Z Z [ [
+ +
≥ ⇔ = ≥
+ +
+
abft}
( )
( )
[
[ [
[
Z
Z
Z
Z
t t
t
t
+ +
=
+
+
+*
a
Z
[
[
Z
Z
Z
t t t t
t
−
−
+ + −
=
+
f′t}⇔t}⇒G.0-ft
LxGGL⇒
[
Z
≤ftz∀tm⇒
[
[ [
[
Z
Z
Z Z
Bài 6. Y<ab≠L:6-
[ [
[ [
a b a b a b
y
b a
b a b a
= + − + + +
÷
Bài 7. Y<
x y+ >
L:676-
[
x y
S
x xy y
+
=
+ +
Bài 8. './QRS#:
x px
P x y z xy yz zx= + + + + +
Bài 12. L:m@L5
( ) ( )
x x x x m− + + − − + =
P
Bài 10 L:m@L5
p px x x x m+ − = − + +
P
Bài 11 L:m@L5
( )
Z
[ [x x x x x x m− + − − + = − +
[PQeP
Bài 12 L:m@L5
Z
x
x mx
x
−
= − +
−
P%_&
Bài 13 L:m@L5
< [ < m x x x m− + − =