Gv: Nguyễ n Phước Vónh Trường THPT Lấp Vò 3
Tit 01. DAO ĐNG ĐIU HA
Ngày son:………. Ngy dy: ………
1. Kin thc:
ωϕ ωωϕ
ω
ωϕ ωππ
2. K năng:
!"#$%
!"#$%
1. Ơn l thuyt (3’): N#i dung c$a ph&n kin thc trên
2. Gi+i bi t-p:42’
&#'&#'%()*+&
,-."# &'&
/0/1'/2,
333
"
,
3
,
3
'/24π*3
/0/1,%ω'/π5π/05167
"
,
ω'/π%/0/1'018,9
,
'
/
ϕ
ϕ
=−
=
5ϕπ)
5*
π
π
"*
π
%/01π?'8,
?*%
π
π
π8,9?ω
*,
?'*
"P,!)FQE<0%
,-."# &'&
(,9'/679R
2
(
)
39393
"
,
39
,
3
SR9S2/2)
5(/2
2
(
,
?S/2
2
(
5?'/2/2
2
(
,
?S
/2
2
(
5?*//2
S
,
T
5S
'//
'
'/)
;U\)P;SR
>;)N#=B0M_C0T;`
;
5T,5,T'%'/'///0','/,%
>;/5R'5R2)
J_0'/'/2,
aaa%bcXbd0aeX6af@JgJhX6i )UW!"#$.=-=B)!;"#$%
Tit 02. CON LC L XO. CON LC ĐƠN
Ngày son: ………. Ngy dy: ………
1. Kin thc:
`?T9π
m
k
9 j
'
,
9j
ω
= +
π
l
g
9j
'
,
9j
,='?α9j
,
,='?α
/
9jj
j
2. K năng:
!"#$%
!"#$%
1. Ơn l thuyt (3’): N#i dung c$a ph&n kin thc trên
2. Gi+i bi t-p:42’
&#'&#%()1+&
,-."# &'&
>
5ϕπ)
/'/ππ,
"E4*;Pωϕ
4
%
*
T
T
π π
π
+ =
5
/
':8 /
v A
a A m s
ω π
ω π
= − =
= − = − <
5
a
k
5,
'
'
T%
π
2
m
k
5,
T%
π
2
'
m m
k
+
"3
S
,
T
o/
/
/0
=
)5
/ '/
π π π
ω
= =
/
/
v
A x
ω
= +
( )
π
)
54/
π
,
&#*%:)8+&
,-."# &'&
,1/9l,9:0o
,
3"α
4/
e
,
3`
,
3
π
l
g
0o
"j
'
,-."# &'&
:0o,
9v5
'
'
/l = 3
'
v
'
v'
π
l
g
v
v/
π
/0'(l
g
−
5
= Acosω(t - ∆t)
π
λ
= −
÷
2
t x
A
T
2. K năng:
!"#$%
!"#$%
1. Ơn l thuyt (2’): N#i dung c$a ph&n kin thc trên
2. Gi+i bi t-p:42’
&#'"#8%()''+&
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3
Gv: Nguyễ n Phước Vónh Trường THPT Lấp Vò 3
,-."# &'&
1@67
T
4*/,3
"
'1//,3
m
f
λ
= =
#z
'011
m
λ
="#o%1)'+&
,-."# &'&
o,'//67
/0o,
A2A
@'
3
"y33
/0o
/0//o /0o
'//
v
m cm
f
λ
= = = =
5o0*~T%/0o~o0*
5'/01~T%~'/01
5T'!)F
5/UO;_"N$=#'UO;r
&#*J)A_.H,)T;[T;G=#44/,0)UW=#'*41,%@H,"UW)T;[
T;G=#1/,;PT;)A_.)UW"UW=#
,-."# &'&
T
44/,
'*41,
{
T
1/,{
3
{
5{
T
44//01((/67
5{
'*41((/0'8,
@)A_.)C,•"L"UW*,%
>; !;Z;L,;A;^)Cq,$;U\)A_.=n;$;;A2=#";CA3
"XKA<=#/0167;P;P<=#";CA3
;
2
T
π
ω
=
; λ = vT;
1
1
10
dB B=
;
0
( ) 10lg
I
L dB
I
=
;
I
0
= 10
-12
W/m
2
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4
2
λ
A
"
/0167
&T
3
]$=AU) l 3λ/4 5λ = '0*,50',
)CH_;C,'u;P l 5λ’/4 5λ = /0o*,5
'
0167
5Bn
'
z
'0167
)CH_;C,u;P λ
2
= 4l/7 = /0(,5
40167
5Bn
z
'08167
)CH_;C,4u;P λ
3
= 4l/9 = /0*8,5
4
*0167
5Bn
4
z
AB =Tλ/2 = *λ/2 / => λ= '/,
" λ5 λ.f = //,
&#*@VH_A.AF;0A&W1670&'o,0)A_.)CH_=#
1/,%)CH_";CA"l%
,-."# &'&
167&'o,
1/,&3
λ1/1,
AB =Tλ/2 = T 'o => có 18 bụng sóng
@H_&;AF;&1/,0)A_.)CH_',0)A)CH_'//67%YL,@
!;,E401,=#u;_"l;M,^_TL€%
,-."# &'&
&1/,',
'//67401,
X;_&;M,^_3
λ'//'//',
=Tzλ/2 = Tz/01 4018%/015Tz8
J_E@=#u;Mo
&#(E,L,I,!;ApH,XApL,,T; X0,MUOH,=#]
:/&%&K
Uƒ;N<H,=#a
/
/0'j,
%bUO<H,E=#";CA3
,-."# &'&
]
:/&a
k
= 1090/340 = 3,2s
=>
40?4/05v
t
= d/
'/://01*1/,
aaa%bcXbd0aeX6af@JgJhX6i„$.,E;…]bK$% )UW!"#$.,E;…]b
K$)!;"#$%
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Gv: Nguyễ n Phước Vónh Trường THPT Lấp Vò 3
()%
Tit 05. Ngày son: …………… Ngy dy: ……………
1. Kin thc:
?<BnS
π
π
?b ,T;!†
]
S]%
?‡AT;!†
b
'Sb%
?w)ˆ†
?@E; _);Uˆa
,
T;†
]
†
b
0R/0S
]b'0†
,
…0R'0‰a
,
…%a
,
?6n)ˆ,-'…'…
'
'…
0,-K$……
'
…
?6ln,-bb
'
b
0,-K$'b'b
'
"†
b
'Sb1Ω9 a‰†
b
*5*
'///ππ
&#"#'4%o)/+&
,-."# &'&
…4/
4Ω
b'4///2`
A
'/ t V
ω
3
"‰
…
3‰
b
3
†
b
'Sb4/Ω9 †
b]
††… −+
(/Ω
a‰†
3
†
]
S]*/Ω9 †
b]
††… −+
*/
Ω9
a‰†
'9ϕ'5ϕπ*
5
'//π?π*
"‰
…
a…*/J9‰
]
a†
]
*/J
&#*"#'4%'/)'+&
,-."# &'&
…4/Š
Gv: Nguyễ n Phước Vónh Trường THPT Lấp Vò 3
Tit 06. Ngày son: ……………Ngy dy: ……………
&#'"#'*%')+&
,-."# &'&
…4/Š]/0'26
b'*///2`
'/ '// u t V
π
=
3
"‰
‡
3
†
b
'Sb*/Ω9 †
]
S]'/Ω9
†
CL
ZZR −+
4/
Ω
a‰†
9ϕ†
]
†
CLL
ZZR −+
*/
Ω
a‰†9ϕ†
]
?†
b
…?'5ϕ?π*)
5
'//ππ*
"‰
]
a%
LL
ZR +
'//J
"#'*%4)+&
,-."# &'&
…4/Š
*/ '// u t V
π
=
4/
Ω9a*
9
JW†
b'
o'//π?π*
JW†
b
o'//ππ*
‰
‡
a%
L
ZR +
//
J
&#*"#'*%1)+&
,-."# &'&
*/ '// u t V
π
=
* '//
(
i t A
Tit 07. Ngày son: ……………. Ngy dy: ……………
&#'"#'*%8)4+&
,-."# &'&
…*/Š]/0126
/ '// u t V
π
=
a*0*b3R3
"a
,
3b3
†
]
1/Ω9†‰a/*0*1/Ω9
†
L C
R Z Z= + −
5
† 1/ */ 4/
L C
Z Z R− − = − =
5
4/
L C
Z Z− = ±
5
'
JW†
b
o/Ωϕ?4*5ϕ/0(*)
JW†
b
/Ωϕ4*5ϕ/0(*)
"bUO;nAl=W;^T;†
]
†
b
1/Ω%
>;
FC
π
1///
'
=
# I
max
= U/R = 220/40 = 5,5A
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Gv: Nguyễ n Phước Vónh Trường THPT Lấp Vò 3
&#"#'*%:)4+&
,-."# &'&
…*/Š
o/'// u t V
π
*/
R RL L
U U U V= − =
9
a‰
…
…*/*/'5†
]
‰
]
a4/Ω5
HL
π
40/
=
†
b
‰
b
a8/'8/Ω5
FC
π
8///
'
=
"
4/ 8/
'5
*/ *
†
b
‰
b
a'801/0''81Ω
†
…]
‰
…]
a1//0'1//Ω
†‰a4801/0'481Ω
1//
481
RL L
L C
Z R Z
Z R Z Z
= + =
= + − =
5†
]
x
x '
x
L
C
Z
LC
Z
ω
= =
5
'81
*//
x
=
ω
ω
*//
% %44/
'81
ω π
=> =
5ω'///π)
5]†
]
ω*//'///π*'/π6
…
ao/Ω9
5†
]
‰
]
a(/Ω95](/'//π6
5†
b
‰
b
a'/Ω95b''//π%'/`
&#"#'1%8)1+&
,-."# &'&
]/0(26
b''*///2`
'(/'// u t V
π
=
Po/j
3
†
]
(/Ω9†
b
'*/Ω9
ϕ
'//
π
%
G; ,T;!0AT;0w)ˆ<,E;%
" JK"LA;MAZ;AE,E;%
c) G;n!$;nAlZ;A,•$;Žn%
,-."# &'&
…'//
4
Ω
]
'
π
60
b1/
π
Œ`
'//
π
†
]
3†
b
3†3
"A3
‰
…
?†
b
…?'
4
5R?
π
()
J_0A//
'//
π
?
π
(J%
‰
…
…%a'%'//
4
'//
4
J0
‰
]
a%†
]
'//J0‰
b
a%†
b
//J0
%€"LA;MUV
a10S'//
π
)
;N=„,a‰
]
†
]
5‰
]
a†
]
41/J
†
b]
††… −+
5†
b]
†† −
/
Ω
%
;N=„,a‰
&
†5‰
&
a†'//J
A
]0b
G;[A^#;n[A^<E,E;&%
,-."# &'&
…'//
Ω
0]/04'o60
b1/
π
µ`0A
&
//
'//
π
J
3
"A
•
3A
•&
3
P 3R3
†
]
S%]'//
Ω
0†
b
π
π
*%
"‰
/•
…%a
/
//J5A
•
//'//
π
π
*J%PA
•
#q$;
‡†
]
k†
b
CA
•&
)L$;
π
W0‰
/•&
a
/
%†
J0n!$;nAlZ;AA ,=#//
1
J0BnmA,E;=#0G;)0]0b%&K;n[
A^<,E;=#
,-."# &'&
A*//'//
π
J
‰
)]
//
1
J
a
)3]3b3
†‰a*//%
'//
Ω
0
R)†5)†%R'//
%
'//
Ω
%
+ −
L C
r Z Z
'//
Ω
%5
] b
† † '//− = Ω
5
b
b
† 4//
† '//
= Ω
= Ω
5
b '/0( `
b 4'0o `
= µ
= µ
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