Đa thức và hàm hữu tỷ - Pdf 67

Chu
.
o
.
ng 2
D
-
ath´u
.
cv`ah`amh˜u
.
uty

2.1 D
-
ath´u
.
c ..................... 44
2.1.1 D
-
ath´u
.
c trˆen tru
.
`o
.
ng sˆo
´
ph´u
.
c C ....... 45

tbiˆe
´
nv´o
.
ihˆe
.
sˆo
´
thuˆo
.
c tru
.
`o
.
ng sˆo
´
P d
u
.
o
.
.
cbiˆe

udiˆe
˜
nd
o
.
n tri

n, a
0
,a
1
,...,a
n
l`a c´ac sˆo
´
;v`amˆo
˜
itˆo

ng da
.
ng (2.1) dˆe
`
u
l`a d
ath´u
.
c.
K´yhiˆe
.
u: Q(z) ∈P[z].
Nˆe
´
u a
0
,a
1

.
c trˆen tru
.
`o
.
ng sˆo
´
thu
.
.
c: Q(z) ∈ R[z].
2.1. D
-
ath´u
.
c 45
Nˆe
´
u Q(z) =0th`ıbˆa
.
ccu

a n´o (k´y hiˆe
.
u degQ(z)) l`a sˆo
´
m˜u cao nhˆa
´
t
cu

td
´o g o
.
il`ahˆe
.
sˆo
´
cao nhˆa
´
t.
Nˆe
´
u P (z)v`aQ(z) ∈P[z] l`a c˘a
.
pd
ath´u
.
cv`aQ(z) =0th`ıtˆo
`
nta
.
i
c˘a
.
pd
ath´u
.
c h(z)v`ar(z) ∈P[z] sao cho
1
+

-
ath´u
.
c trˆen tru
.
`o
.
ng sˆo
´
ph´u
.
c C
Gia

su
.

Q(z) ∈ C[z]. Nˆe
´
u thay z bo
.

isˆo
´
α th`ı ta thu d
u
.
o
.
.

.
.
cgo
.
il`anghiˆe
.
m
cu

ad
ath´u
.
c Q(z) hay cu

aphu
.
o
.
ng tr`ınh d
a
.
isˆo
´
Q(z)=0.
D
-
i
.
nh l´y Descate. D
ath´u

mbˆo
.
i m cu

ad
ath´u
.
c Q(z)
nˆe
´
uv`achı

nˆe
´
u Q(z) chia hˆe
´
tcho(z − α)
m
nhu
.
ng khˆong chia hˆe
´
tcho
(z − α)
m+1
.Sˆo
´
m du
.
o

.
pho
.
.
psˆo
´
ph´u
.
c C d
u
.
o
.
.
clˆa
.
pnˆenb˘a
`
ng
c´ach gh´ep thˆem v`ao cho tˆa
.
pho
.
.
psˆo
´
thu
.
.
c R mˆo

.
mph´u
.
c thu
.
.
csu
.
.
.Dod
´o khˆong cˆa
`
n pha

i
s´ang ta
.
o thˆem c´ac sˆo
´
m´o
.
id
ˆe

gia

iphu
.
o
.

ba

ncu

ad
a
.
isˆo
´
).
46 Chu
.
o
.
ng 2. D
-
ath´u
.
c v`a h`am h˜u
.
uty

Mo
.
idath´u
.
cd
a
.
isˆo

.
qua

sau.
1
+
Mo
.
idath´u
.
cbˆa
.
c n (n  1) trˆen tru
.
`o
.
ng sˆo
´
ph´u
.
cd
ˆe
`
uc´od´ung n
nghiˆe
.
mnˆe
´
umˆo
˜

(z − α
2
)
m
2
···(z − α
k
)
m
k
, (2.2)
trong d
´o α
i
= α
j
∀ i = j v`a m
1
+ m
2
+ ···+ m
k
= n.
D
ath´u
.
c (2.1) v´o
.
ihˆe
.

i m cu

adath´u
.
c Q(z)th`ısˆo
´
ph´u
.
cliˆen ho
.
.
p
v´o
.
in´o
z
0
l`a nghiˆe
.
mbˆo
.
i m cu

adath´u
.
c liˆen ho
.
.
p
Q(z), trong d´o d a

2.1.2 D
-
ath´u
.
c trˆen tru
.
`o
.
ng sˆo
´
thu
.
.
c R
Gia

su
.

Q(z)=z
n
+ a
1
z
n−1
+ ···+ a
n−1
z + a
n
(2.4)

.
t sau dˆa y .
D
-
i
.
nh l´y 2.1.1. Nˆe
´
usˆo
´
ph´u
.
c α l`a nghiˆe
.
mbˆo
.
i m cu

ad
ath´u
.
c (2.4) v´o
.
i
hˆe
.
sˆo
´
thu
.

.
nh l´y trˆen dˆay ta c´o thˆe

t`ım khai triˆe

ndath´u
.
cv´o
.
ihˆe
.
sˆo
´
thu
.
.
c Q(z) th`anh t´ıch c´ac th`u
.
asˆo
´
.Vˆe
`
sau ta thu
.
`o
.
ng chı

x´et d
a

ul`ax thay cho z.
2.1. D
-
ath´u
.
c 47
D
-
i
.
nh l´y 2.1.2. Gia

su
.

d
ath´u
.
c Q(x) c´o c´ac nghiˆe
.
m thu
.
.
c b
1
,b
2
,...,b
m
v´o

v`a a
2
,...,a
n
v`a a
n
v´o
.
ibˆo
.
itu
.
o
.
ng ´u
.
ng λ
1

2
,...,λ
n
. Khi d´o
Q(x)=(x− b
1
)
β
1
(x− b
2

n
x + q
b
)
λ
n
. (2.5)
D
-
i
.
nh l´y 2.1.3. Nˆe
´
ud
ath´u
.
c Q(x)=x
n
+ a
1
x
n−1
+ ···+ a
n−1
x + a
n
v´o
.
ihˆe
.

id
ath´u
.
cv´o
.
ihˆe
.
sˆo
´
h˜u
.
uty

ta c´o
D
-
i
.
nh l´y 2.1.4. Nˆe
´
u phˆan sˆo
´
tˆo
´
i gia

n

m
(, m ∈ Z,m>0) l`a nghiˆe

+···+a
n−1
x+
a
n
=0th`ı  l`a u
.
´o
.
ccu

asˆo
´
ha
.
ng tu
.
.
do a
n
v`a m l`a u
.
´o
.
ccu

ahˆe
.
sˆo
´

n
.Ch´u
.
ng
minh r˘a
`
ng:
1
+
Nˆe
´
u P (z) ∈ C[z]th`ıP (z)=P (z).
2
+
Nˆe
´
u P (z) ∈ R[z]th`ıP (z)=P (z).
Gia

i. 1
+
´
Ap du
.
ng c´ac t´ınh chˆa
´
tcu

a ph´ep to´an lˆa
´

n−1
+ ···+ a
n−1
z + a
n
= a
0
(z)
n
+ a
1
(z)
n−1
+ ···+ a
n−1
z + a
n
= P (z).
48 Chu
.
o
.
ng 2. D
-
ath´u
.
c v`a h`am h˜u
.
uty


n−1
z + a
n
= a
0
(z)
n
+ a
1
(z)
n−1
+ ···+ a
n−1
z + a
n
= a
0
(z)
n
+ a
1
(z)
n−1
+ ···+ a
n−1
z + a
n
= P (z).
T`u
.

+ a
1
z
n−1
+ ···+ a
n−1
z + a
n
,a
0
=0
th`ı sˆo
´
ph´u
.
c liˆen ho
.
.
p
a l`a nghiˆe
.
mbˆo
.
i m cu

adath´u
.
c
P (z)=a
0

.
1 ta c´o
P (z)=P (z). (2.6)
V`ı a l`a nghiˆe
.
mbˆo
.
i m cu

a P (z)nˆen
P (z)=(z − a)
m
Q(z),Q(a) = 0 (2.7)
trong d
´o Q(z)l`adath´u
.
cbˆa
.
c n − m.T`u
.
(2.6) v`a (2.7) suy ra
P (z)=P (z)=(z − a)
m
Q(z)=(z − a)
m
Q(z). (2.8)
Ta c`on cˆa
`
nch´u
.

u n`ay vˆo l´y. B˘a
`
ng c´ach d˘a
.
t t = z,t`u
.
(2.8) thu d
u
.
o
.
.
c
P (t)=(t − a)
m
Q(t), Q(a) =0.
2.1. D
-
ath´u
.
c 49
D˘a

ng th´u
.
c n`ay ch´u
.
ng to

r˘a

.
i
hˆe
.
sˆo
´
thu
.
.
c P (z)=a
0
z
n
+ a
1
z
n−1
+ ···+ a
n
(a
0
= 0) th`ı sˆo
´
ph´u
.
c liˆen
ho
.
.
p

trong d
´o Q(z)l`adath´u
.
cbˆa
.
c n − m v`a Q(a) =0.
Ta cˆa
`
nch´u
.
ng minh r˘a
`
ng
P (z)=(z −
a)
m
Q(z),Q(a) =0. (2.11)
Thˆa
.
tvˆa
.
yt`u
.
(2.9) v`a (2.10) ta c´o
P (z)=
(z − a)
m
Q(z)=(z − a)
m
· Q(z)

ihˆe
.
sˆo
´
thu
.
.
cth`ı
Q(t)=Q(t). 
V´ı du
.
4. Gia

iphu
.
o
.
ng tr`ınh z
3
− 4z
2
+4z − 3=0.
Gia

i. T`u
.
d
i
.
nh l´y 4 suy r˘a

.
.
do a = −3. Sˆo
´
ha
.
ng tu
.
.
do
50 Chu
.
o
.
ng 2. D
-
ath´u
.
c v`a h`am h˜u
.
uty

a = −3 c´o c´ac u
.
´o
.
cl`a±1, ±3. B˘a
`
ng c´ach kiˆe


z −
1
2
− i

3
2

hay l`a phu
.
o
.
ng tr`ınh d
˜a cho c´o ba nghiˆe
.
ml`a
z
0
=3,z
1
=
1
2
− i

3
2
; z
2
=

ng:
1
+
t´ıch c´ac th`u
.
asˆo
´
tuyˆe
´
n t´ınh;
2
+
t´ıch c´ac th`u
.
asˆo
´
tuyˆe
´
n t´ınh v´o
.
i tam th´u
.
cbˆa
.
c hai v´o
.
ihˆe
.
sˆo
´

= −

3,z
2
=

3,z
3
=1+i,
z
4
=1− i, z
5
= −1+i, z
6
= −1 − i.
T`u
.
d
´o
1
+
P
6
(z)=(z−

3)(z +

3)(z−1−i)(z−1+i)(z +1−i)(z +1+i)
2

u
.
o
.
.
c
P
6
(z)=(z −

3)(z +

3)(z
2
− 2z + 2)(z
2
+2z +2). 
V´ı d u
.
6. T`ım d
ath´u
.
chˆe
.
sˆo
´
thu
.
.
cc´olu˜yth`u

sˆo
´
thu
.
.
cnˆen c´ac nghiˆe
.
mph´u
.
c xuˆa
´
thiˆe
.
n
t`u
.
ng c˘a
.
p liˆen ho
.
.
pph´u
.
c, ngh˜ıa l`a nˆe
´
u z
2
=2− i l`a nghiˆe
.
mcu

n t´ınh.
Gia

i. Ta c´o
P (x)=(x +1)
n
− (x − 1)
n
=[x
n
+ nx
n−1
+ ...]− [x
n
− nx
n−1
+ ...]=2nx
n−1
+ ...
Nhu
.
vˆa
.
y P (x)l`ad
ath´u
.
cbˆa
.
c n − 1v´o
.

,k=1, 2,...,n− 1.
Do d
´o
(x +1)
n
− (x − 1)
n
=2n

x − icotg
π
n

x − icotg

n

···

x − icotg
(n − 1)π
n

.
Khi phˆan t´ıch d
ath´u
.
c trˆen tru
.
`o

.
`o
.
ng P d
´o. Nh˜u
.
ng d
ath´u
.
cn`ayd
u
.
o
.
.
cgo
.
il`ad
a
th´u
.
cbˆa
´
t kha

quy.
Ch˘a

ng ha
.


Nhờ tải bản gốc

Tài liệu, ebook tham khảo khác

Music ♫

Copyright: Tài liệu đại học © DMCA.com Protection Status